The Meaning of -1.#IND

Question

I have been running into a problem where some of my doubles have been assigned the value -1.#IND, and I have absolutely no idea what it means or how exactly to catch it.

Any help on the issue would be much appreciated.

Kind Regards, Alex

I believe my question is a duplicate, sorry about that! – Alex Feb 16 '14 at 17:35 — Alex, Feb 16 '14 at 17:35

score 1 · Accepted Answer · answered Feb 16 '14 at 17:25

1

-1.#IND It is Negative indefinite NaN. http://blogs.msdn.com/b/oldnewthing/archive/2013/02/21/10395734.aspx

answered Feb 16 '14 at 17:25

Avt

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No, it's not negative infinity. It's an "indefinite" value, which is a special type of NaN (whereas an infinity is not a NaN). Read the article. – C. K. Young Feb 16 '14 at 17:27
Yes, my mistake. I have changed the answer. – Avt Feb 16 '14 at 17:28

score 0 · Answer 2 · answered Feb 16 '14 at 17:31

-1.#IND

according to this article

is the Indefinite NaN, which is a special type of quiet NaN generated under specific conditions. If you perform an invalid arithmetic operation like add positive infinity and negative infinity, or take the square root of a negative number, then the IEEE standard requires that the result be a quiet NaN, but it doesn't appear to specify what quiet NaN exactly. Different floating point processor manufacturers chose different paths. The term Indefinite NaN refers to this special quiet NaN, whatever the processor ends up choosing it to be.

The Meaning of -1.#IND

2 Answers2