HTML class names with php variables

Question

I have a massive page but I have recconstructed the error in a JS FIDDLE

<li><input class="<?php echo $env;?>" type="checkbox" > This is Item 1</li>

This is the line that has the error.

It is not reading the class name as what the variable is equal too?

am i missing something or can you not do this ?

Have you copied and pasted your code into the JSFiddle? Because you're not closing your first PHP tag. — George, Feb 18 '14 at 11:32
JSFiddle can't run PHP. [Similar topic](http://stackoverflow.com/questions/4616159/is-there-a-php-sandbox-something-like-jsfiddle-is-to-js) — Vucko, Feb 18 '14 at 11:34
no i get nothing and yes i have corrected the copy and paste issue now — RixsonL, Feb 18 '14 at 11:38
have a look at http://jsfiddle.net/qsJ5R/8/ I assume that is what you are trying to do — mic, Feb 18 '14 at 11:42
yes but that class obviously has to be dynamic thats why its a variable — RixsonL, Feb 18 '14 at 12:04

Vinod VT · Accepted Answer · 2014-02-18T11:41:02.883

Change your HTML as

<body>
<a href="http://jquery.com/">jQuery</a>
<?php $env = "env" ?>
        <ul class="chk-container">
           <li><input class="selecctall" type="checkbox"> Selecct All</li>
           <li><input class="<?php echo $env;?>" type="checkbox" > This is Item 1</li>
           <li><input class="checkbox1" type="checkbox" > This is Item 2</li>
           <li><input class="checkbox1" type="checkbox" > This is Item 3</li>
           <li><input class="checkbox1" type="checkbox" > This is Item 4</li>
           <li><input class="checkbox1" type="checkbox" > This is Item 5</li>
           <li><input class="checkbox1" type="checkbox" > This is Item 6</li>
           <li><input class="checkbox2" type="checkbox" > Do not select this</li>

        </ul>
</body>

The problem is that, you are not closing the php tag

sorry that was just a copy and paste issue thats not the actual problem sorry — RixsonL, Feb 18 '14 at 11:37

HTML class names with php variables

1 Answers1