ERROR rotate image with php

Question

Hello I'm trying to rotate an image with php as follows, I get the image in base64 and rotaciono, but when I try to turn it again into a base64 error as I do that emerges?

$img64=$_POST['IMG'];
$img = str_replace('data:image/jpeg;base64,', '', $img64);
$img = str_replace(' ', '+', $img);
$data = base64_decode($img);
$source     = imagecreatefromstring($data);
$rotate     = imagerotate($source, 90, 0); // if want to rotate the image

$data = base64_encode($rotate);//ERROR

Error:

<b>Warning</b>:  base64_encode() expects parameter 1 to be string, resource given in <b>C:\EasyPHP-DevServer-13.1VC9\data\localweb\projects\STEP\php\rotateLand.php</b> on line <b>9</b><br />

would it hurt to use jquery to rotate the image? – rockStar Feb 21 '14 at 19:03 — rockStar, Feb 21 '14 at 19:03

score 0 · Accepted Answer · edited May 23 '17 at 12:28

0

You're trying to pass an image object to base64_encode, which only takes a string as a parameter.

Take a look at this question regarding converting an image object to a string for base64 encoding.

edited May 23 '17 at 12:28

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answered Feb 21 '14 at 19:04

Lucas Penney

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score 0 · Answer 2 · edited May 23 '17 at 12:20

0

$rotate isn't a string; it's an image resource. Unfortunately there's no easy way to turn it into a string - you have to use output buffering. Have a look at this answer.

edited May 23 '17 at 12:20

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answered Feb 21 '14 at 19:04

George Brighton

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score 0 · Answer 3 · answered Feb 25 '14 at 14:47

Grateful for help, my code looked like this. problem solved

$img64  = $_POST['IMG'];
$img    = str_replace('data:image/jpeg;base64,', '', $img64);
$img    = str_replace(' ', '+', $img);
$data   = base64_decode($img);
$source = imagecreatefromstring($data);
$rotate = imagerotate($source, $_POST['rot'], 0);

ob_start();
imagejpeg($rotate);
$contents =  ob_get_contents();
ob_end_clean();

echo $rotate = base64_encode($contents);?>

ERROR rotate image with php

3 Answers3