How can I stop Java from shortening large double?

Question

Let's suppose we have the following code:

System.out.println(String.valueOf(100000000000.0));

Now the output to that is 1.0E11. But that is not what I want. (Looks bad on a highscore) I want it to output exactly 100000000000.0. Is there a way to do that?

@HotLicks Would be better if you have posted an answer showing how — Bren, Feb 22 '14 at 13:41
Are you sure your high scores should be doubles in the first place? Even if fractional scores are allowed, I would be rather surprised to find that scoring 0.1 points and then 0.2 points was very slightly different from scoring 0.3 points. — user2357112, Feb 22 '14 at 13:48

score 6 · Accepted Answer · answered Feb 22 '14 at 13:43

6

Format it appropriately. For example:

System.out.printf("%.1f", 1654621658874684.0);

Be aware that double is not infinitely precise. It has a precision of about 15 to 17 decimal digits. If you need floating-point numbers with arbitrary precision, use BigDecimal instead of double.

Or you could use String.format():

System.out.println(String.format("%.0f", 1654621658874684.0d));

answered Feb 22 '14 at 13:43

Ima Vafaei

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Thanks! That provided me with everything I needed, and added some additional useful information. – Jonas Bartkowski Feb 22 '14 at 14:13

score 2 · Answer 2 · answered Feb 22 '14 at 13:40

2

System.out.printf("Score: %.0f\n", 1e5); will print 100000.

answered Feb 22 '14 at 13:40

tkroman

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score 0 · Answer 3 · edited May 23 '17 at 10:26

0

Refer to this ... Quest
You can use DecimalFormat to format your value for displaying

edited May 23 '17 at 10:26

Community

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answered Feb 22 '14 at 13:46

RamValli

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score 0 · Answer 4 · answered Feb 22 '14 at 14:07

0

For those kind of big numbers, I think you should use BigDecimal.

answered Feb 22 '14 at 14:07

wonhee

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How can I stop Java from shortening large double?

4 Answers4