Is it possible to not destruct obj while destructor is running?

Question

If I override the destructor of my class, is it possible to made some check in it if that instance should be killed or sent to a pool? I want to make simple to reuse the obj, the user only needs to free it (or leave for compiler) and the destructor would check if that's reusable.

ReusableClass::~ReusableClass() {
  if (x == 1) {
    // abort destructor, send to pool
  }
}

Maybe you should consider something like a smart pointer with a custom deleter. — Fred Larson, Feb 25 '14 at 21:29
Do you want to reuse the object itself, or merely the memory/space occupied by the object? — Oliver Charlesworth, Feb 25 '14 at 21:29
Take a look at [reference counting](http://en.wikipedia.org/wiki/Reference_counting) and [std::shared_ptr](http://www.cplusplus.com/reference/memory/shared_ptr/). — jliv902, Feb 25 '14 at 21:43

score 4 · Accepted Answer · answered Feb 25 '14 at 21:32

4

Once the destructor of an object started running the object is considered dead: 12.4 [class.dtor] paragraph 14:

Once a destructor is invoked for an object, the object no longer exists; ...

answered Feb 25 '14 at 21:32

Dietmar Kühl

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score 0 · Answer 2 · answered Feb 25 '14 at 21:35

Of course not - you would have no reference to the object either - how could you recycle the object then?

So solve that problem and you'll have the solution. Use a smart pointer and store the reference wherever you actually need it, perhaps in a map or owned by another object (this is now looking more like a Java solution, for instance), or manually delete it (this is less smart) when ready.

Is it possible to not destruct obj while destructor is running?

2 Answers2