UISegmentedControl deselect (make none of the segments selected)

Question

in fact the title contains my question. I have a UISegmentedControl, and need to deselect currently selected tab. I tried:

[menu setSelectedSegmentIndex:-1];

menu being the UBOutlet for uisegmentedcontrol but this gives me exception. anyone have some idea? thanks peter

I'd also suggest using UISegmentedControlNoSegment instead of -1 - it's not a source of problem here but just in case — Vladimir, Feb 05 '10 at 09:48
2010-02-05 11:10:16.799 Gazetapl[30839:20b] *** -[NSCFArray length]: unrecognized selector sent to instance 0x3d39ed0 [Session started at 2010-02-05 11:10:16 +0100.] 2010-02-05 11:10:16.800 Gazetapl[30839:20b] *** Terminating app due to uncaught exception 'NSInvalidArgumentException', reason: '*** -[NSCFArray length]: unrecognized selector sent to instance 0x3d39ed0' 2010-02-05 11:10:16.802 Gazetapl[30839:20b] Stack: ( — dusker, Feb 05 '10 at 10:10

Calin Drule · Answer 1 · 2021-12-23T13:40:40.447

254

The right way to do this is:

[menu setSelectedSegmentIndex:UISegmentedControlNoSegment];

Edit:

Swift 5:

menu.selectedSegmentIndex = UISegmentedControl.noSegment

edited Dec 23 '21 at 13:40

answered Feb 06 '12 at 18:11

Calin Drule

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11

I do not understand why OP does not select this answer!. – Ali Nov 10 '14 at 04:39
1

@Ali because this wasn't his question. He was already doing this (mostly) correctly. His problem was elsewhere as I explained. – David Kanarek Nov 17 '14 at 17:16
@DavidKanarek but it really doesn't make sense, this is the answer and I had the same problem, I googled it, this was the first google result, and this is the answer, strange, also in the question I can't see any other code or exceptions..! – Boda Sep 14 '15 at 07:14

score 32 · Answer 2 · edited Oct 19 '20 at 07:05

Setting the segmentedControl to .momentary = YES changes the way the user can interact with the segmentedControl. If you want to have nothing selected initially when the page loads but have segmentedControl behave the same after a selection is made by the user then you will want something more like this:

Swift 4 solution:

 @IBOutlet weak var segmentedControl: UISegmentedControl!

 self.segmentedControl.selectedSegmentIndex = UISegmentedControlNoSegment

Swift 5.1:

 self.segmentedControl.selectedSegmentIndex = UISegmentedControl.noSegment

score 31 · Answer 3 · answered May 19 '11 at 18:00

31

I guess you try to create a momentary selection in segmented control. In interface builder set the segmentedcontrol to momentary. Or in code you can do:

menu.momentary = YES;

answered May 19 '11 at 18:00

dombesz

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Momentary will still result in a segment being selected on load. Besides, use of Momentary should only be because you actually want a Momentary segment control, not just to try to force no segment selection. Use the UISegmentedControlNoSegment solution. – Michael Peterson Apr 01 '16 at 20:28

score 8 · Answer 4 · answered Nov 22 '19 at 20:42

I did class which supports this kind of interaction:

class UIDeselectableSegmentedControl: UISegmentedControl {

    override func touchesEnded(_ touches: Set<UITouch>, with event: UIEvent?) {
        let previousSelectedSegmentIndex = self.selectedSegmentIndex

        super.touchesEnded(touches, with: event)

        if previousSelectedSegmentIndex == self.selectedSegmentIndex {

            self.selectedSegmentIndex = UISegmentedControl.noSegment
            let touch = touches.first!
            let touchLocation = touch.location(in: self)
            if bounds.contains(touchLocation) {
                self.sendActions(for: .valueChanged)
            }
        }
    }
}

The main advantage of that is that you just need to modify which class the Storyboard/Xib/ViewCode is using and this will work like a charm ;]

score 7 · Answer 5 · answered Dec 20 '18 at 06:33

7

swift 4

@IBOutlet weak var segmentControl: UISegmentedControl! {
    didSet {
        segmentControl.selectedSegmentIndex = UISegmentedControl.noSegment
    }
}

answered Dec 20 '18 at 06:33

Kerim Khasbulatov

692
8
21

score 3 · Answer 6 · answered Oct 11 '14 at 09:21

3

You can now do this in xcode 6 in the interface builder:

Deselect the 'Selected' option under segmented control behaviour in attributes inspector.

answered Oct 11 '14 at 09:21

Zaxter

2,939
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score 2 · Answer 7 · answered Nov 20 '15 at 03:47

2

The Swift solution: @IBOutlet weak var mySegmentedControl: UISegmentedControl! and mySegmentedControl.selectedSegmentIndex = -1.

answered Nov 20 '15 at 03:47

Tom Daniel

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score -1 · Accepted Answer · answered Feb 05 '10 at 17:29

-1

I would assume that you've called [myArray length] instead of the proper [myArray count] somewhere in your code. NSArray uses the count method, not length for the number of items it contains.

answered Feb 05 '10 at 17:29

David Kanarek

12,611
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3

hi, i don't understand. what does this have to do with uisegmentedcontrol – dusker Feb 07 '10 at 21:17
1

Nothing directly, but based on the exception you posted, the problem is not with UISegementedControl. Perhaps somewhere in your handling of changing the selected segment you access an array. – David Kanarek Feb 08 '10 at 01:18
4

Why the down vote? Mine is the only answer that actually addresses the problem dusker was having. – David Kanarek Nov 17 '14 at 17:17
Actually, your answer does not address the question. The op wants to deselect a segment from a UISegmentedController. – Uzaak Dec 23 '15 at 14:18
2

The OP asked the wrong question (can be clearly seen by the exception), this is the correct answer. It addresses the problem 100%. – oyalhi Jan 16 '16 at 18:58
What a tangent. But I commend your insight. – carlossless Apr 01 '16 at 09:18
2

This doesn't answer the question of how to have no option selected at all...swift option below show be the accepted answer. – csmith Apr 28 '17 at 02:49

UISegmentedControl deselect (make none of the segments selected)

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