wxPython RichTextCtrl with strikethrough

Question

I want to set text with strike-through in RichTextCtrl of wxPython. But could not find any method like BeginStrikethrough or SetStrikethrough.

Is it possible to apply strike-through in RichTextCtrl? How?

EDIT 1:

Font with strike-through flag used with BeginFont and EndFont not giving strike-through effect

import wx
import wx.richtext as rt

class MyFrame(wx.Frame):
    def __init__(self):
        wx.Frame.__init__(self, None, 1, 'Testing strike-through')
        rtc = rt.RichTextCtrl(self, -1)
        rtc.WriteText("normal text")
        rtc.Newline()

        font = wx.FFont(12, wx.FONTFAMILY_DEFAULT, face='Tahoma', flags=wx.FONTFLAG_STRIKETHROUGH)
        rtc.BeginFont(font)
        rtc.WriteText("This is strike-through")
        rtc.EndFont()

if __name__ == '__main__':
    app = wx.PySimpleApp()
    frame = MyFrame()
    frame.Show()
    app.MainLoop()

Output:

No strike-through in output

I don't see that function, but it does have a `BeginFont` function, so you could create a font with strikethrough, and use it that way. — Corley Brigman, Feb 27 '14 at 17:29
Hi @CorleyBrigman, I tried `BeginFont` and `EndFont` but not giving strike-through effect. See **EDIT 1** in question. — arvinchhi, Feb 27 '14 at 18:56
I haven't actually used it myself, but it looks like there is another answer below that works. — Corley Brigman, Feb 28 '14 at 15:03

Jerry_Y · Accepted Answer · 2014-02-28T09:29:16.967

enter image description here

You can use font.SetStrikethrough(True) with wxpython2.9.4 or higher, refer This Link
Otherwise: use font.SetNativeFontInfoFromString(str) to set the flag with Native info description.

Please check the following string to see the difference, only tested in windows:

desc without Strikethrough: 0;-16;0;0;0;400;0;0;0;1;0;0;2;32;Tahoma

desc with Strikethrough: 0;-16;0;0;0;400;0;0;1;1;0;0;2;32;Tahoma

Code:

import wx
import wx.richtext as rt

class MyFrame(wx.Frame):
    def __init__(self):
        wx.Frame.__init__(self, None, 1, 'Testing strike-through')
        rtc = rt.RichTextCtrl(self, -1)
        rtc.WriteText("normal text")
        rtc.Newline()

        font = wx.FFont(12, wx.FONTFAMILY_DEFAULT, face='Tahoma', flags=wx.FONTFLAG_STRIKETHROUGH)

        info = font.GetNativeFontInfoDesc()
        info = self.setFontInfoStrikethrough(info)
        font.SetNativeFontInfoFromString(info)

        rtc.BeginFont(font)
        rtc.WriteText("This is strike-through")
        rtc.EndFont()

    def setFontInfoStrikethrough(self, info):
        print "orig:", info
        info = info.split(";")
        info[8] = r'1'
        info = ";".join(info)
        print "new :",info
        return info

if __name__ == '__main__':
    app = wx.PySimpleApp()
    frame = MyFrame()
    frame.Show()
    app.MainLoop()

Thnx @Jerry_Y, the **otherwise** approach you provided worked very well for me. I am using wxPython2.8 so its great that I dont need to upgrade to 2.9 or higher.. thnx again :) — arvinchhi, Feb 28 '14 at 15:28

score 0 · Answer 2 · answered Sep 17 '19 at 14:13

You can use a text effect, this works with wxPython 2.8.12 too:

style = rt.TextAttrEx()
style.SetFlags(rt.TEXT_ATTR_EFFECTS)
style.SetTextEffects(rt.TEXT_ATTR_EFFECT_STRIKETHROUGH)
style.SetTextEffectFlags(rt.TEXT_ATTR_EFFECT_STRIKETHROUGH)
rtc.BeginStyle(style)
rtc.WriteText("This is strike-through")
rtc.EndStyle()

(tested on Linux)

wxPython RichTextCtrl with strikethrough

2 Answers2