Multiple words not getting searched , not taking space

Question

when i pass string with space in bw the words to the servlet and run the android aaplication error comes like this

03-01 09:32:41.110: E/Excepiton(1301): java.io.FileNotFoundException: http//address of server:8088/First/MyServlet?ads_title=test test&city=Pune

here ads_title=test test and city = Delhi

but it works fine when i pass single word string like ads_title=test and city = Delhi

but when i run query on sql with both the value that works that means query is fine.

String stringURL="http//laddress of server:8088/First/MyServlet" +
String.format("?ads_title=%s&city=%s",editText1.getText(),City);

that is where i am passing the values

Take a look at this: http://stackoverflow.com/questions/10786042/java-url-encoding — Ulrich Thomas Gabor, Mar 01 '14 at 12:52
If I understand the question, i think you need to use %20 instead of a space. — Ted Bigham, Mar 01 '14 at 12:52
strRegUrl=strRegUrl.replaceAll(" ", "%20"); best way worked for me tnx Guys happy developing — tinos07, Mar 02 '14 at 21:30

score 2 · Answer 1 · answered Mar 01 '14 at 13:06

Data sent as a URL must be "encoded" to ensure that all the data passes properly to the server to be interpreted correctly. Fortunately, Java provides a standard class URLEncoder and the encoding specified by the World Wide Web Consortium is "UTF-8 so, use

String finalURL = URLEncoder(stringURL,"UTF-8");

(That way you don't have to know what the encoding is for each special character.)

score 1 · Accepted Answer · edited May 23 '17 at 10:26

1

I agree with the comments (not sure why they didn't post as an answer though?) - you want to try encoding your URL - so that the space is handled correctly (%20)

Java URL encoding of query string parameters

edited May 23 '17 at 10:26

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answered Mar 01 '14 at 12:55

monojohnny

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Multiple words not getting searched , not taking space

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