no enclosing instance of type... in scope

Question

I investigate java inner classes.

I wrote example:

public class Outer {
    public Outer(int a){}

    public class Inner {
        public Inner(String str, Boolean b){}
    }

    public static class Nested extends Inner{
        public static void m(){
            System.out.println("hello");
        }
        public Nested(String str, Boolean b , Number nm)   { super("2",true);   }
    }

    public class InnerTest extends Nested{
        public InnerTest(){  super("str",true,12);  }
    }
}

I invoke it from main using following string:

 new Outer(1).new Inner("",true);

I see compile error:

  java: no enclosing instance of type testInheritancefromInner.Outer is in scope

Can you explain me this situation?

UPDATE

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See http://stackoverflow.com/questions/9560600/java-no-enclosing-instance-of-type-foo-is-accessible — Raedwald, Mar 02 '16 at 22:38

score 21 · Accepted Answer · edited May 23 '17 at 12:17

Inner is an inner class. It can only be created when there is an enclosing instance of the class containing the Inner class definition.

However, you've created a static nested class, Nested, which extends from this class. When you try to invoke the super constructor

public Nested(String str, Boolean b , Number nm)   { super("2",true);   }

it will fail because the super constructor, for Inner, depends on an instance of Outer, which doesn't exist in the static context of the Nested class. Jon Skeet provides a solution.

An explanation of the solution appears in the JLS here.

Superclass constructor invocations may be subdivided:

Unqualified superclass constructor invocations begin with the keyword super (possibly prefaced with explicit type arguments).

Qualified superclass constructor invocations begin with a Primary expression.

They allow a subclass constructor to explicitly specify the newly created object's immediately enclosing instance with respect to the direct superclass (§8.1.3). This may be necessary when the superclass is an inner class.

score 20 · Answer 2 · answered Mar 01 '14 at 16:41

As Sotirios has said, your nested (not-inner) class doesn't implicitly have an instance of Outer to effectively provide to the Inner.

You can get round this, however, by explicitly specifying it before the .super part:

public Nested(String str, Boolean b, Number nm) { 
    new Outer(10).super("2", true);
}

Or even accept it as a parameter:

public Nested(Outer outer) { 
    outer.super("2", true);
}

However, I would strongly advise you to avoid such convoluted code. I avoid nested classes most of the time, named inner classes almost always, and I can't ever remember using a combination of them like this.

the reference to an instance of outer class to use in a constructor like `outer.super()` can be not only a parameter, but also a field. This way you can quietly extend an inner class being outside its outer class. — Alexei Kaigorodov, Oct 06 '17 at 23:48

no enclosing instance of type... in scope

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