How to use UUIDs with Hibernate as a field?

Question

I'm trying to use generated UUIDs without @Id annotation, because my primary key is something else. The application does not generate an UUID, do you have an idea?

This is my declaration:

@Column(name = "APP_UUID", unique = true)
@GeneratedValue(generator="system-uuid")
@GenericGenerator(name="system-uuid", strategy = "uuid")
private String uuid;

I'm using Hibernate 4.3.0 with Oracle10g.

Have you found the solution yet? I'm having the same problem. — rand0m86, Jul 01 '14 at 13:02

score 10 · Answer 1 · answered Oct 14 '15 at 14:37

Check the Javadoc of GeneratedValue:

Provides for the specification of generation strategies for the values of primary keys.

With other words - it is not possible with just an annotation to initialize a 'none ID' attribute.

But you can use @PrePersist:

@PrePersist
public void initializeUUID() {
    if (uuid == null) {
        uuid = UUID.randomUUID().toString();
    }
}

Engineer · Accepted Answer · 2014-03-03T15:11:27.113

6

try this it may help

@Id
@GeneratedValue(generator = "hibernate-uuid")
@GenericGenerator(name = "uuid", strategy = "uuid2")
@Column(name = "uuid", unique = true)
private String uuid;

read this link read hibernate documents it is possible

edited Mar 03 '14 at 15:11

answered Mar 03 '14 at 14:47

Engineer

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1

I used your solution without the @Id annotation. No improvement :/ – Florian Mozart Mar 03 '14 at 14:58
Eclipse throws an error:"This class has a composite primary key. It must use an ID class." – Florian Mozart Mar 03 '14 at 15:23
2

@Engineer - you should add more explanations to your answer. Links can become obsolete. It's definitely appropriate to cite sources, but you should provide a proper, full response. – Olimpiu POP Aug 22 '15 at 20:38
1

`Unable to build Hibernate SessionFactory: Caused by: org.hibernate.AnnotationException: Unknown Id.generator: hibernate-uuid` – EpicPandaForce Feb 08 '16 at 14:49
3

isn't it possible to have it generated without @Id annotation. I dont want my column to be a primary key. – Obaid Maroof Feb 12 '16 at 10:55
2

This does not answer the question. – dryleaf Nov 25 '19 at 02:28

score 2 · Answer 3 · answered Mar 03 '14 at 15:08

2

It's not because your UUID is a primary key that it's mandatory to have it annoted with @GeneratedValue.

For example, you can do something like this :

public class MyClass
{
   @Id
   private String uuid;

   public MyClass() {}

   public MyClass (String uuid) {
      this.uuid = uuid;
   }
}

And in your app, generate a UUID before saving your entity :

String uuid = UUID.randomUUID().toString();
em.persist(new MyClass(uuid)); // em : entity manager

answered Mar 03 '14 at 15:08

user3173787

87
7

I know the chance to have an UUID twice is very unlikely, but it could happen. That's why I wanted hibernate to manage UUIDs. Thank you for your help – Florian Mozart Mar 03 '14 at 15:36
Hibernate does _nothing_ to prevent an ID - conflict (especially it does not generate a new value if the first value exists in the database already) – Tobias Liefke Oct 14 '15 at 15:25

How to use UUIDs with Hibernate as a field?

3 Answers3