How delete first 10 characters in String?

Question

I have an array of string, it apron random figures, for example:"475759403048575663648495004945757590" . How can I remove the first 10 digits ?

Read the documentation or do some research online. This is a Java question, not an Android question. [Documentation](http://docs.oracle.com/javase/7/docs/api/java/lang/String.html) — BLaZuRE, Mar 04 '14 at 06:10
dude u asked the same thing yesterday and I didn't get any feedback at all.. http://stackoverflow.com/a/22143547/3239917 — MCollard, Mar 04 '14 at 07:39

score 6 · Answer 1 · answered Mar 04 '14 at 06:12

6

You can use substring() method from Java's String class like below code,

String str = "475759403048575663648495004945757590"
str = str.substring(10);

answered Mar 04 '14 at 06:12

Lucifer

Shailendra Madda · Answer 2 · 2014-03-04T06:19:30.900

1

Use substring method of String class :

String removeSubString = "475759403048575663648495004945757590"
   removeSubString = removeString.substring(10);

edited Mar 04 '14 at 06:19

answered Mar 04 '14 at 06:10

Shailendra Madda

`getText()` *doesn't* return a string? – user2864740 Mar 04 '14 at 06:11
`getText()` is used to get Text data from `EditText` – MDMalik Mar 04 '14 at 06:16

score 1 · Answer 3 · answered Mar 04 '14 at 06:23

You can use substring(int beginIndex) method of String class which returns a new string that is a substring of this string.

   String str="4785214522396554786324";
   str=str.substring(10);

It will form String starting from 10th index till end of String.

3 Answers3