Limit string to some number of characters

Question

I`m trying to do the next task: I have a string, for ex. "Product with a very long name so that it goes on to more than one line". I want to make next customization: if a number of charackters in the string (without spaces) will be more than 22, cut it on the last word, and add "...".

Cool, then do it. If you don't know how, post your current code and ask a question. — Prinzhorn, Mar 04 '14 at 13:01
^ The answer I gave in this question includes a much prettier CSS solution, which factors in the fact that llllllllll is nowhere near as "long" as WWWWWWWWWW. — Niet the Dark Absol, Mar 04 '14 at 13:03
I have read your solution with CSS. But, how does the browser know how many characters I want to left? And, will it be cross-browser solution? — volodymyr3131, Mar 04 '14 at 13:12
But, as I understand, it will cut the string at the 50 character in your example. And I need the last word to be full — volodymyr3131, Mar 04 '14 at 13:39
I think what you are looking for is some think like http://webwidetutor.com/php/substring/ — Mubo, Mar 04 '14 at 14:24
A have already found answer: http://stackoverflow.com/a/17702942/2938377 — volodymyr3131, Mar 04 '14 at 14:40
The answer I found abowe is not quite right(( This algoritm cut the phrase after 22 symbols, including spaces. But I need to count 22 symbols in text without spaces, and then add '...' after the last full word. Please, has anyone some ideas? — volodymyr3131, Mar 06 '14 at 12:03

Jaykishan · Answer 1 · 2014-03-05T06:40:09.363

1

<?php
  if(strlen($yourString) > 22)
    $rest = substr($yourString, 22,-1)."...";
  else
    $rest = $yourString;
  echo $rest;
?>

If you want that last word doesn't cut then,

<?php
$yourString = "bla blaaa bla blllla bla bla";
$out = "";
if(strlen($yourString) > 22) {
    while(strlen($yourString) > 22) {
        $pos = strrpos($yourString, " ");
        if($pos !== false && $pos <= 22) {
            $out = substr($yourString,0,$pos);
            break;
        } else {
            $yourString = substr($yourString,0,$pos);
            continue;
        }
    }
} else {
    $out = $yourString;
}
echo "Output String: ".$out;
?>

edited Mar 05 '14 at 06:40

answered Mar 04 '14 at 13:04

Jaykishan

1,409
1
15
26

What if `$yourString` is already less than the max length? – Niet the Dark Absol Mar 04 '14 at 13:04
@NiettheDarkAbsol yes man..i forget that condition – Jaykishan Mar 04 '14 at 13:08
In my case it returned: ry long name so that it goes on to more than one lin... And it is not correct.. Also, I need the last word to be full, not cut as in this example – volodymyr3131 Mar 04 '14 at 13:19
Do you want that last word don't cut? – Jaykishan Mar 04 '14 at 13:22
Yes) I want to add "..." after the last full word, when the total number of characters (without spaces) will be less than 22. So, it may be 15 characters at the last word, when with the next word it will be summary 24 characters – volodymyr3131 Mar 04 '14 at 13:29
Check the updated answer, If works I want u to optimize this answer. All the best – Jaykishan Mar 04 '14 at 13:48
No, unfortunely it doesn`t work( It shows only b letter – volodymyr3131 Mar 04 '14 at 14:47
@volodymyr3131 i had told you to optimize this. See the updated code – Jaykishan Mar 05 '14 at 06:41

score 0 · Answer 2 · answered Mar 04 '14 at 13:08

0

if(strlen($myString)>=22)
{
  $result = substr($myString, 0, 22)."...";
}
else
{
  $result = $myString;
}

answered Mar 04 '14 at 13:08

user2706194

199
8

A little comment wouldn't harm – nKn Mar 04 '14 at 13:26

score -1 · Answer 3 · answered Mar 04 '14 at 13:02

-1

You can do like this:

<?php
$text = "A very long woooooooooooord.";
if(strlen($text) > 22 ) {
 echo substr($text, 1, 22)."..";
} else {
echo $text;
}

?>

answered Mar 04 '14 at 13:02

Suresh Kamrushi

15,627
13
75
90

The OP wants to **cut** a string after X characters, *not* span it into different lines. – Amal Murali Mar 04 '14 at 13:03
@AmalMurali correct the post – Suresh Kamrushi Mar 04 '14 at 13:07
What do you mean? Correct what? – Amal Murali Mar 04 '14 at 13:15
No, it doesn`t work in the way I need – volodymyr3131 Mar 04 '14 at 14:48

Limit string to some number of characters

3 Answers3