How do I run multiple servlet after single submit button click?

Question

I want to run two servlet when I click submit button in html page Here is servlet and html code

package com.serv;

import java.io.IOException;
import java.io.PrintWriter;

import javax.servlet.ServletException;
import javax.servlet.annotation.WebServlet;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;

/**
 * Servlet implementation class MyServlet
 */
@WebServlet("/MyServlet")
public class MyServlet extends HttpServlet {
    private static final long serialVersionUID = 1L;

/**
 * @see HttpServlet#doPost(HttpServletRequest request, HttpServletResponse response)
 */
protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
    // TODO Auto-generated method stub
        response.setContentType("text/html");
        PrintWriter out = response.getWriter();
        try {
            String user=request.getParameter("user");
            out.println("<h2>"+user+"</h2>");
        } catch (Exception e) {
            // TODO Auto-generated catch block
            e.printStackTrace();
        }

        }

}

here is 2nd servlet

package com.serv;

import java.io.IOException;
import java.io.PrintWriter;

import javax.servlet.ServletException;
import javax.servlet.annotation.WebServlet;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;

/**
 * Servlet implementation class MyServlet2
 */
@WebServlet("/MyServlet2")
public class MyServlet2 extends HttpServlet {
private static final long serialVersionUID = 1L;

/**
 * @see HttpServlet#doGet(HttpServletRequest request, HttpServletResponse response)
 */
protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
    // TODO Auto-generated method stub
    response.setContentType("text/html");
    PrintWriter out1=response.getWriter();
    try {
        String user1=request.getParameter("user1");
        out1.println("<h2>"+user1+"</h2>");
    } catch (Exception e) {
        // TODO Auto-generated catch block
        e.printStackTrace();
    }
}

}

Here is HTML file

<html>
<head>
<meta charset="UTF-8">
<title>Insert title here</title>
</head>
<body>
    <form method="post" action="MyServlet">
        Name<input type="text" name="user">

    </form>
    <form method="post" action="MyServlet2">
        Sir Name<input type="text" name="user1">
    <input type="submit" value="submit">
    </form>

    </body>
</html>

I tried placing submit button at different places but its not working . Can some tell me how shall i write the code so both servlet will be called

a servlet can handle only one http request, you can create a filter(s) if you need pre-procecessing — Athanor, Mar 04 '14 at 13:26
What would be the use case for that? Usually there should be 1:1 mapping from request to servlet. If you want multiple things to happen, your servlet should make different calls into the business layer. — Gyro Gearless, Mar 04 '14 at 13:47

score 0 · Answer 1 · edited May 23 '17 at 10:26

One solution could be to intercept the request with a filter, and forward to both doPost methods from it.

This could help you:

How to use a servlet filter in Java to change an incoming servlet request url?

Another solution would be to make a forward from one servlet to the other. If you can modify the servlets, probably this is better than the filter.

Take a look at this:

http://www.devmanuals.com/tutorials/java/servlet/RequestDispatcher/forward.html

You could also resolve it sending two requests from the browser, using JavaScript, but I understand the scope of the problem is limited to Java.

Keerthivasan · Accepted Answer · 2014-03-04T13:57:47.637

0

You can pass the request from one servlet to the other using

Request.getRequestDispatcher(String).forward() or Request.getRequestDispatcher(String).include()

based on how you would like to handle the response generated by the servlets. I'm not clear why are you getting user and user1 parameter in different servlets. Instead do everything in a Single Servlet class. Please take a look at Servlet filters mainly intended to preliminary processing of the requests. Read about Servlet Fiters to make use of them appropriately

edited Mar 04 '14 at 13:57

answered Mar 04 '14 at 13:37

Keerthivasan

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I just want to display servlet contents – user1121210 Mar 04 '14 at 13:40
Yes you can make use of `include()` method to do it – Keerthivasan Mar 04 '14 at 13:42
I need to display both servlet output at same time will it work ? – user1121210 Mar 04 '14 at 13:55
yes, it will just create a single response after the second servlet processes the request – Keerthivasan Mar 04 '14 at 13:58
I did following RequestDispatcher rs = request.getRequestDispatcher(getServletName()); rs.include(request, response); its not working can you please tell what mistake i am doing ? – user1121210 Mar 05 '14 at 06:04
You have to provide the url mapped to the servlet in `request.getRequestDispatcher("/urlmappedtoservlet");` – Keerthivasan Mar 05 '14 at 06:17
let us [continue this discussion in chat](http://chat.stackoverflow.com/rooms/49020/discussion-between-user1121210-and-octopus) – user1121210 Mar 05 '14 at 07:00

How do I run multiple servlet after single submit button click?

2 Answers2