TimeAgo - Year and Month ago

Question

My unixtime is 1336608000

which is exactly 2012-5-10.

1 year 10 months ago from today - 2014-03-06

Now what I want to do is output the year and month ago as it is. so I want to display:

1 year 10 months ago.

The most timeAgo functions I see here in Stackoverflow and all over the internet shows the time ago as "2 years ago" which is wrong. I have tried like 8-10 php functions to display the exact month count

So my question is, Is there a php time ago function that shows the exact year and month count instead of rounding it up?

Thanks

Since you don't seem to want to do the work yourself, this is a library/tool request, which is off-topic. — Lightness Races in Orbit, Mar 05 '14 at 23:58
I think you got me wrong. I am not that good of a PHP developer. — Towfiq, Mar 05 '14 at 23:59
That doesn't change what this site is and isn't for, I'm afraid. Please read the FAQ in future before posting, though you should know after almost 4 years that this is neither a library recommendation website, nor a code generator, nor a message board/forum. — Lightness Races in Orbit, Mar 06 '14 at 00:00

score 1 · Accepted Answer · edited May 23 '17 at 11:45

I found this answer by Glavić and it works perfectly.

I tweaked it for you...

Usage: echo time_elapsed_string('2012-5-10', true);

function time_elapsed_string($datetime, $full = false) {
    $now = new DateTime;
    $ago = new DateTime($datetime);
    $diff = $now->diff($ago);

    $diff->w = floor($diff->d / 7);
    $diff->d -= $diff->w * 7;

    $string = array(
        'y' => 'year',
        'm' => 'month',
    );
    foreach ($string as $k => &$v) {
        if ($diff->$k) {
            $v = $diff->$k . ' ' . $v;
        } else {
            unset($string[$k]);
        }
    }

    if (!$full) $string = array_slice($string, 0, 1);
    return $string ? implode(', ', $string) . ' ago' : 'just now';
}

TimeAgo - Year and Month ago

1 Answers1