How I can avoid automatic type coercion when comparing numbers in Javascript?

Question

I want to know how I can avoid automatic coercion when comparing numbers using the less than and higher than operator in JavaScript.

For example, I already know that == operator makes type coercion, for example:

1 == '1'; //true

And === operator doesn't, for example:

1 === '1'; // false

But, how I can avoid this when comparing numbers?, for example:

1<2; //true
1<'2'; //true
1<'0'; //false

I want to avoid this automatic type coercion.

You could always do fun stiff like : `typeof a === typeof b && a < b` — epascarello, Mar 06 '14 at 15:35
There is no fun on RTTI, but this solution sounds enough (for now) — dseminara, Mar 07 '14 at 16:14
Possible duplicate of [Overloading Arithmetic Operators in JavaScript?](http://stackoverflow.com/questions/1634341/overloading-arithmetic-operators-in-javascript) — Paul Sweatte, Feb 10 '17 at 03:35

Paul Sweatte · Answer 1 · 2017-09-20T08:56:50.493

Use boxing via the RegExp literal. For example:

console.log(/3.1/ > 3);
console.log(/3.1/.exec(3.1) > 3)
console.log((/Infinity/).toString().replace(/\//g,"") > 3)

or NumberFormat:

console.log(new Intl.NumberFormat({}, {'style':'percent'}).format(2) > 1)

References

1 Answers1