How to check not in array element

Question

I am trying to check if an element is not in array than want to redirect page: My code is as below:

$id = $access_data['Privilege']['id']; 

if(!in_array($id,$user_access_arr))
{
    $this->Session->setFlash(__('Access Denied! You are not eligible to access this.'), 'flash_custom_success');
    return $this->redirect(array('controller'=>'Dashboard','action'=>'index'));
}

I am confused how to check if element is not in array. As we can check element exist or not in array using in_array function of PHP. I am trying to check it using (!in_array) but I did not got result.

$id = 31; $user_access_arr = ([0] => 4,[1] => 8,[2] => 12,[3] => 31) — s4suryapal, Mar 11 '14 at 05:12
So as you can see `31` value exist in your array. So in_array will return true. — Rikesh, Mar 11 '14 at 05:13
`if(!in_array($id,$user_access_arr))` not working in this case because you already have the value of id in your `$user_access_arr` array — jogesh_pi, Mar 11 '14 at 05:19
$id = 31; $user_access_arr = ([0] => 4,[1] => 8,[2] => 12) if array value is like this than what will be the result — s4suryapal, Mar 20 '14 at 05:37

score 102 · Answer 1 · answered Sep 08 '16 at 05:41

102

Simply

$os = array("Mac", "NT", "Irix", "Linux");
if (!in_array("BB", $os)) {
    echo "BB is not found";
}

answered Sep 08 '16 at 05:41

Elyor

5,396
8
48
76

Tomas Kaidl · Answer 2 · 2017-09-14T09:53:39.163

21

I prefer this

if(in_array($id,$user_access_arr) == false)

respective

if (in_array(search_value, array) == false) 
// value is not in array

edited Sep 14 '17 at 09:53

answered Sep 14 '17 at 08:31

Tomas Kaidl

211
2
4

What is for OP? – Tomas Kaidl Sep 14 '17 at 09:23
Excuse me, that's the original poster so in this case the person asking a question. It helps if answers are explained.https://stackoverflow.com/help/how-to-answer – Edwin Sep 14 '17 at 09:32
Yeah, but more than answer for OP are answers here for people searching similar problems, I guess. > How to check not in array element in php – Tomas Kaidl Sep 14 '17 at 09:40

score 7 · Answer 3 · edited Jun 29 '15 at 09:45

7

if (in_array($id,$user_access_arr)==0)
{
    $this->Session->setFlash(__('Access Denied! You are not eligible to access this.'), 'flash_custom_success');
    return $this->redirect(array('controller'=>'Dashboard','action'=>'index'));
}

edited Jun 29 '15 at 09:45

Yeldar Kurmangaliyev

33,467
12
59
101

answered Jun 29 '15 at 09:32

Shruti

71
1
3

score 7 · Answer 4 · edited Sep 19 '17 at 11:55

7

$id = $access_data['Privilege']['id']; 

if(!in_array($id,$user_access_arr));
    $user_access_arr[] = $id;
    $this->Session->setFlash(__('Access Denied! You are not eligible to access this.'), 'flash_custom_success');
    return $this->redirect(array('controller'=>'Dashboard','action'=>'index'));

edited Sep 19 '17 at 11:55

pr1nc3

8,108
3
23
36

answered Jun 26 '17 at 08:23

Umesh Pimpale

71
1
2

score 5 · Answer 5 · answered May 30 '14 at 08:21

Try with array_intersect method

$id = $access_data['Privilege']['id']; 

if(count(array_intersect($id,$user_access_arr)) == 0){

$this->Session->setFlash(__('Access Denied! You are not eligible to access this.'), 'flash_custom_success');
return $this->redirect(array('controller'=>'Dashboard','action'=>'index'));
}

ackuser · Answer 6 · 2014-06-18T14:43:49.940

3

I think everything that you need is array_key_exists:

if (!array_key_exists('id', $access_data['Privilege'])) {
                $this->Session->setFlash(__('Access Denied! You are not eligible to access this.'), 'flash_custom_success');
                return $this->redirect(array('controller' => 'Dashboard', 'action' => 'index'));
            }

edited Jun 18 '14 at 14:43

answered Jun 18 '14 at 14:20

ackuser

5,681
5
40
48

score 3 · Answer 7 · answered Nov 27 '14 at 05:31

3

$array1 = "Orange";
$array2 = array("Apple","Grapes","Orange","Pineapple");
if(in_array($array1,$array2)){
    echo $array1.' exists in array2';
}else{
    echo $array1.'does not exists in array2';
}

answered Nov 27 '14 at 05:31

aish

623
1
7
11

Shafiqul Islam · Answer 8 · 2017-03-30T08:51:55.270

you can check using php in_array() built in function

<?php
  $os = array("Mac", "NT", "Irix", "Linux");
  if (in_array("Irix", $os)) {
    echo "Got Irix";
 }
 if (in_array("mac", $os)) {
  echo "Got mac";
}
?>

and you can also check using this

<?php
  $search_array = array('first' => 1, 'second' => 4);
  if (array_key_exists('first', $search_array)) {
    echo "The 'first' element is in the array";
   }
   ?>

in_array() is fine if you're only checking but if you need to check that a value exists and return the associated key, array_search is a better option.

$data = array(
0 => 'Key1',
1 => 'Key2'
);

$key = array_search('Key2', $data);

if ($key) {
 echo 'Key is ' . $key;
} else {
 echo 'Key not found';
}

for more details http://php.net/manual/en/function.in-array.php

score 0 · Answer 9 · answered Mar 03 '21 at 07:48

0

$data = array(
0 => 'Key1',
1 => 'Key2'
);

$key = array_search('Key2', $data);

if ($key) {
 echo 'Key is ' . $key;
} else {
 echo 'Key not found';
}

answered Mar 03 '21 at 07:48

Request Data

1

2

Thank you for this code snippet, which might provide some limited, immediate help. A [proper explanation](https://meta.stackexchange.com/q/114762/349538) would greatly improve its long-term value by showing why this is a good solution to the problem and would make it more useful to future readers with other, similar questions. Please [edit] your answer to add some explanation, including the assumptions you’ve made. – jasie Mar 03 '21 at 09:42

How to check not in array element

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