Reverse sort the dictionary by value

Question

I have the following dictionary, sorted ascendingly by value.

>>> x = {'foo': 2.01, 'bar': 4.11, 'qux':3.2, 'ail':1.2, 'dfa':0.03}
>>> sorted_x = sorted(x.iteritems(), key=operator.itemgetter(1))
>>> sorted_x
[('dfa', 0.029999999999999999), ('ail', 1.2), ('foo', 2.0099999999999998), ('qux', 3.2000000000000002), ('bar', 4.1100000000000003)]

How can I do sort it descendingly by value? I tried this but prints nothing

>>> sorted_x.reverse()
>>>

"I tried this but prints nothing" Did you try checking `sorted_x` after that? — Karl Knechtel, Sep 14 '22 at 13:59

score 3 · Answer 1 · answered Mar 12 '14 at 13:19

3

You can use the reverse=True when you're sorting:

>>> sorted(x.iteritems(), key=operator.itemgetter(1), reverse=True)

[('bar', 4.11), ('qux', 3.2), ('foo', 2.01), ('ail', 1.2), ('dfa', 0.03)]

answered Mar 12 '14 at 13:19

Lipis

21,388
20
94
121

score 1 · Answer 2 · answered Mar 12 '14 at 13:20

1

In [143]:

import operator
x = {'foo': 2.01, 'bar': 4.11, 'qux':3.2, 'ail':1.2, 'dfa':0.03}
sorted_x = sorted(x.iteritems(), key=operator.itemgetter(1), reverse=True)
sorted_x
Out[143]:
[('bar', 4.11), ('qux', 3.2), ('foo', 2.01), ('ail', 1.2), ('dfa', 0.03)]

answered Mar 12 '14 at 13:20

EdChum

376,765
198
813
562

why would you both flag the question as duplicate and give an answer? – njzk2 Mar 12 '14 at 13:31
@njzk2 I posted the answer first and then saw the duplicate – EdChum Mar 12 '14 at 13:34

score 1 · Answer 3 · answered Mar 12 '14 at 13:25

1

Try this:

>>> x = {'foo': 2.01, 'bar': 4.11, 'qux':3.2, 'ail':1.2, 'dfa':0.03}
>>> sorted_x = sorted(x.iteritems(), key=operator.itemgetter(1), reverse=True)
>>> sorted_x
[('bar', 4.11), ('qux', 3.2), ('foo', 2.01), ('ail', 1.2), ('dfa', 0.03)]

answered Mar 12 '14 at 13:25

turnt

3,235
5
23
39

Reverse sort the dictionary by value

3 Answers3