What is the purpose when assign a named function to a different variable name?

Question

Just to carify, I'm not asking the difference of function declaration and function variable.

For example:

var Klass = function() {};
Klass.prototype._fn1 = function fn1() {};
Klass.prototype._fn2 = function fn2() {};

So, my question is what is the purpose of doing this? Why can't just write:

var Klass = function() {};
Klass.prototype._fn1 = function() {}; // <-- note that the function has no name, it just be assigned to the object as a property
Klass.prototype._fn2 = function() {};

It provides a way for the inner scope to access itself locally. Otherwise, there's no reason I can think of — Ian, Mar 12 '14 at 14:23
http://stackoverflow.com/questions/310870/use-of-prototype-vs-this-in-javascript — Etheryte, Mar 12 '14 at 14:23
He's not asking about OO, he's asking about the name `fn` in the expression `function fn()` — Barmar, Mar 12 '14 at 14:24
Check the duplicated question, there are several answers and at least 1 is what you are looking for — Huangism, Mar 12 '14 at 14:30
@Ian You are right. Removed my comment. It was posted before the OP's edit. — Boaz, Mar 12 '14 at 14:45

score -1 · Answer 1 · answered Mar 12 '14 at 14:23

-1

Basically this means you are adding the method _fn1() to Klass Constructor.

Klass.prototype._fn1 = function fn1() {};

And this method is available over the object which is made by using Klass() Constructor.

myObj = new Klass();
myObj._fn1() //you can access the method like this

answered Mar 12 '14 at 14:23

Suman Bogati

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you forgot the dot, myObj._fn1() – Huangism Mar 12 '14 at 14:25
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But what is the purpose of the name `fn1`? That's what his question is asking. – Barmar Mar 12 '14 at 14:25
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I.e. why isn't it `Klass.prototype._fn1 = function() {}`? – Barmar Mar 12 '14 at 14:26

What is the purpose when assign a named function to a different variable name?

1 Answers1