How to modify file names in bash

Question

I have a directory like: /data/work/files/

calldata_phonecalls_2131201401_01.zip calldata_phonecalls_7373201401_02.zip

In this directory I want to create new files corresponding to the zipfiles like , but modifying a small part of the name in BASH:

calldata_calllog_2131201401_01.tsv calldata_calllog_7373201401_02.tsv

pl note "phonecalls" changed to "calllog"

Pl help.

devnull · Accepted Answer · 2014-03-12T17:57:06.870

4

for f in /data/work/files/*.zip; do
  mv "$f" "$(basename "${f/phonecalls/calllog}" .zip).tsv"
done

Using rename (part of perl distribution):

rename 's/phonecalls/calllog/;s/\.zip$/.tsv/' /data/work/files/*.zip

edited Mar 12 '14 at 17:57

answered Mar 12 '14 at 17:35

devnull

@HomayounAfshari Didn't notice that; should be fixed now. – devnull Mar 12 '14 at 17:42
@user1189851 Modifications in name? – devnull Mar 12 '14 at 17:45
excuse me @devnull, can you explain how ${f/x/y} works? – Farvardin Mar 12 '14 at 17:46
1

@HomayounAfshari It'd replace _x_ with _y_. – devnull Mar 12 '14 at 17:48
is it evaluated by bash? – Farvardin Mar 12 '14 at 17:49
2

@HomayounAfshari Yes, it's called shell parameter expansion. See the link in the edit above. – devnull Mar 12 '14 at 17:51

score 1 · Answer 2 · edited May 23 '17 at 11:49

Using rename :

Using one version of rename:

rename 's/^fgh/jkl/' fgh*

Using another version of rename :

rename fgh jkl fgh*

You should check your platform's man page to see which of the above applies.

Using mv:

find ./ -name "*.xyz\[*\]" | while read line
do 
mv "$line" ${line%.*}.xyz
done

Another way

ls -1 | nawk '/foo-bar-/{old=$0;gsub(/-\(.*\)/,"",$0);system("mv \""old"\" "$0)}'

Yet another:

for f in fgh*; do mv $f $(echo $f | sed 's/^fgh/jkl/g'); done

There are several other answers under stackoverflow and superuser pages:

Copied/summarized from the following links:

2 Answers2