Python 2.6.4 property decorators not working

Question

I've seen many examples online and in this forum of how to create properties in Python with special getters and setters. However, I can't get the special getter and setter methods to execute, nor can I use the @property decorator to transform a property as readonly.

I'm using Python 2.6.4 and here is my code. Different methods to use properties are employed, but neither work.

class PathInfo:
    def __init__(self, path):
        self.setpath(path)

    def getpath(self):
        return self.__path

    def setpath(self, path):
        if not path:
            raise TypeError

        if path.endswith('/'):
            path = path[:-1]

        self.__path = path
        self.dirname = os.path.dirname(path)
        self.basename = os.path.basename(path)
        (self.rootname, self.dext) = os.path.splitext(self.basename) 
        self.ext = self.dext[1:]

    path = property(fget=getpath, fset=setpath)

    @property
    def isdir(self):
        return os.path.isdir(self.__path)

    @property
    def isfile(self):
        return os.path.isfile(self.__path)

score 22 · Accepted Answer · answered Feb 10 '10 at 21:09

22

PathInfo must subclass object.

Like this:

class PathInfo(object):

Properties work only on new style classes.

answered Feb 10 '10 at 21:09

gruszczy

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Not just properties, but descriptors of all kinds. – Ignacio Vazquez-Abrams Feb 10 '10 at 21:11
Another option is to put `__metaclass__=type` at the top of the file, which will make all the classes newstyle. I think it's better to be explicit for each class though – John La Rooy Feb 10 '10 at 21:20
Or you can put this `__metaclass__` into the class instead of putting it at the top of the file. This way only one class will have it. – gruszczy Feb 10 '10 at 21:39
1

What a difference a word makes! Thanks for all of your tips. – Matt Norris Feb 10 '10 at 22:46

Python 2.6.4 property decorators not working

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