Posting data, but now what?

Question

I am a newbie to android development so please be patient with me.

I am trying to post user id and password to a PHP page and return data (page working fine, tested and returns Json data).

I followed online guides and had similar problem to:

How to send data to a website using httpPost, app crashes

So I followed what was said in the following Answer within the above post https://stackoverflow.com/a/18588948/3415061

No more Errors , but now how do I control what happens after data returned and if valid how do I go to the next screen and display it?

The following function executes the request but how I do I get the response to the screen if valid or not.

@Override
protected Boolean doInBackground(Void... params) {
    HttpClient httpclient = new DefaultHttpClient();
    HttpPost httppost = new HttpPost("http://www.blag.com/blag.php");
    try {
         List<NameValuePair> nameValuePairs = new ArrayList<NameValuePair>(3);
        nameValuePairs.add(new BasicNameValuePair("acc", "blag"));
        nameValuePairs.add(new BasicNameValuePair("usr", "blag"));
        nameValuePairs.add(new BasicNameValuePair("pass", "blag"));

        httppost.setEntity(new UrlEncodedFormEntity(nameValuePairs));
        HttpResponse response = httpclient.execute(httppost);
        return true;
    } catch (ClientProtocolException e) {
        e.printStackTrace();
    } catch (IOException e) {
        e.printStackTrace();
    }
    return false ;
}

Or am I suppose to access the response in here, but I tried to launch another screen from here but I got errors.

protected void onPostExecute(Boolean result) {
    super.onPostExecute(result);
    if(result){
        //successful request
    }else{
        //error in request response
    }
   // msgTextField.setText(""); // clear text box
}

Am I taking the correct approach to doing this?

Thanks in advance!!!

new code:

protected void onPostExecute(String result) {
    super.onPostExecute(result);
    if(result=="HEllO"){
        //successful request


            Intent dashboard = new Intent(getApplicationContext(), MainOrder.class);         
            dashboard.addFlags(Intent.FLAG_ACTIVITY_CLEAR_TOP);
            startActivity(dashboard);

        //userFunction.logoutUser(getActivity().getApplicationContext());
    }else{
        //error in request response
    }
   // msgTextField.setText(""); // clear text box
}

error on GetApplicationContext: The method getApplicationContext() is undefined for the type NetRequestAsync

and error on line Command StartActivity The method startActivity(Intent) is undefined for the type NetRequestAsync

now what do you exactly want? you want to parse that response? — M A., Mar 15 '14 at 16:00
I want to start a new screen (intent),if the response is good and pass the data across to the new screen. I have created the new screen but I am getting errors in code when trying to call the screen. here is the latest code — yas, Mar 15 '14 at 16:58
protected void onPostExecute(String result) { super.onPostExecute(result); if(result=="HEllO"){ //successful request Intent dashboard = new Intent(getApplicationContext(), MainOrder.class); dashboard.addFlags(Intent.FLAG_ACTIVITY_CLEAR_TOP); startActivity(dashboard); }else{ //error in request response } // msgTextField.setText(""); // clear text box } — yas, Mar 15 '14 at 16:59

score 0 · Accepted Answer · answered Mar 15 '14 at 17:11

0

If this code is inside an Activity of name, let's say MyCoolActivity, then you can access those methods with MyCoolActivity.this.getApplicationContext() and MyCoolActivity.this.startIntent()

answered Mar 15 '14 at 17:11

Juan Sánchez

980
2
10
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Sorry I dont understand, the intent code is inside a function called onPostExecute, which is inside a class called NetRequestAsync. I am trying to load a form from onPostExecute, but I have errors in code (red underline). the errors I have mentioned at the bottom of the question. – yas Mar 15 '14 at 17:20
Usually those classes like your `NetRequestAsync` class are contained inside an `Activity` class. If it is not your case, then you must pass the current `Activity` to this class as a parameter. Put the complete code of the file containing your class, so helping you will be easier. – Juan Sánchez Mar 15 '14 at 17:39
juan, thnx, that was the problem, I had the netrequestAsync in different class. like i said, i was reading online guide and i presumed i was suppose to create it in a new class. I moved class into mainactivity and its now showing the new screen. – yas Mar 15 '14 at 17:51

Posting data, but now what?

1 Answers1