Error using preg_replace function

Question

I want to replace only

<span class="google-src-text" style="direction: ltr; text-align: left">any character</span>

line by line with space in this source http://persianfox.ir/html.html and my php code is

$content = file_get_contents('path/to/html.html');
$content = str_replace('>', ">\n", $content);

echo preg_replace('/<span class="google-src-text" style="direction: ltr; text-align: left">.*.<\/span>/', ' ', $content);

but this code will replace all the content that beign with <span class="google-src-text" style="direction: ltr; text-align: left"> and last </span>.

Andresch Serj · Answer 1 · 2014-03-17T09:01:25.487

1

This one works if you have no HTML in your "any character".

/<span class="google-src-text" style="direction: ltr; text-align: left">([^<]{1,})<\/span>/

edited Mar 17 '14 at 09:01

answered Mar 17 '14 at 08:47

Andresch Serj

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score 1 · Accepted Answer · edited May 23 '17 at 12:05

* is greedy by default, you need to change it to lazy, like so:

preg_replace('/<span class="google-src-text" style="direction: ltr; text-align: left">.*?<\/span>/', ' ', $content);
//                                                               Note the question mark ^

This will match *up to the first </span>, note that if you have a nested span inside, it will not fetch all the way to the end.

That's why You shouldn't parse HTML with Regex and should instead use a proper HTML DOM parser

Error using preg_replace function

2 Answers2