Python iterate through lists within tuple data structure

Question

I have the following data structure:

data = (['test1','test2','test3'], ['foo1','foo2','foo3'], ['bar1','bar2','bar3'])

I want to iterate through this data structure and create a new tuple which appends position 1 of each list to it. I would like to create a data structure with

(test1,foo1,bar1), (test2,foo2,bar2), (test3,foo3,bar3)

These are not valid data structures, you are missing commas. — placeybordeaux, Mar 17 '14 at 18:01
I just wrote it to outline what it looks like...My apologies — Ciaran, Mar 17 '14 at 18:02
possible duplicate of [Matrix Transpose in Python](http://stackoverflow.com/questions/4937491/matrix-transpose-in-python) — mgilson, Mar 17 '14 at 18:04

score 3 · Answer 1 · answered Mar 17 '14 at 18:01

3

This is an easy zip with argument unpacking:

print zip(*data)

e.g.:

>>> data = (['test1','test2','test3'],['foo1','foo2','foo3'],['bar1','bar2','bar3'])
>>> zip(*data)
[('test1', 'foo1', 'bar1'), ('test2', 'foo2', 'bar2'), ('test3', 'foo3', 'bar3')]

answered Mar 17 '14 at 18:01

mgilson

300,191
65
633
696

score 3 · Answer 2 · edited May 23 '17 at 11:49

3

Unzip it via zip():

>>> data = (['test1','test2','test3'],['foo1','foo2','foo3'],['bar1','bar2','bar3'])
>>> zip(*data)
[('test1', 'foo1', 'bar1'), ('test2', 'foo2', 'bar2'), ('test3', 'foo3', 'bar3')]

Also see: Unzipping and the * operator.

edited May 23 '17 at 11:49

Community

1
1

answered Mar 17 '14 at 18:01

alecxe

462,703
120
1,088
1,195

Python iterate through lists within tuple data structure

2 Answers2