How do I instantiate a class given its string name?

Question

I have an abstract class and I want to initalize it to a class that extends it.

I have the child classes name as a string.

Besides this...

String childClassString;
MyAbstractClass myObject;

if (childClassString = "myExtenedObjectA")
    myObject = new ExtenedObjectA();
if (childClassString = "myExtenedObjectB")
    myObject = new ExtenedObjectB();

How can I do this? Basically how do I get rid of the if statements here?

Does this answer your question? [Create an instance of a class from a string](https://stackoverflow.com/questions/223952/create-an-instance-of-a-class-from-a-string) — GSerg, May 25 '21 at 17:03

score 141 · Accepted Answer · answered Feb 11 '10 at 20:47

141

Look at Activator.CreateInstance().

myObject = (MyAbstractClass)Activator.CreateInstance("AssemblyName", "TypeName");

or

var type = Type.GetType("MyFullyQualifiedTypeName");
var myObject = (MyAbstractClass)Activator.CreateInstance(type);

answered Feb 11 '10 at 20:47

Seth Petry-Johnson

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9

Worked like a charm. In case anybody has problems getting the fully qualified name, this piece of code is helpful ' string typex = typeof(classname).AssemblyQualifiedName; – Sanjit Misra Jun 21 '13 at 10:50
2

Even though the `GetType` documentation for its `typeName` parameter says "The assembly-qualified name of the type", you don't actually need to include the assembly name. If the type is in the calling assembly, just the namespace-qualified type name is sufficient. – Edward Brey May 22 '15 at 15:43

score 24 · Answer 2 · edited Jun 20 '20 at 09:12

24

I believe this should work:

myObject = (MyAbstractClass)Activator.CreateInstance(null, childClassString);

The null in the first parameter defaults to the current executing assembly. For more reference: MSDN

edit: forgot to cast to MyAbstractClass

edited Jun 20 '20 at 09:12

Community

1
1

answered Feb 11 '10 at 20:53

IAbstract

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score 10 · Answer 3 · answered Apr 02 '17 at 22:58

I had some difficulty implementing some of the answers here because I was trying to instantiate an object from a different assembly (but in the same solution). So I thought I'd post what I found to work.

First, the Activator.CreateInstance method has several overloads. If you just call Activator.CreateInstance(Type.GetType("MyObj")), that assumes the object is defined in the current assembly, and it returns a MyObj.

If you call it as recommended in the answers here: Activator.CreateInstance(string AssemblyName, string FullyQualifiedObjectName), then it instead returns an ObjectHandle, and you need to call Unwrap() on it to get your object. This overload is useful when trying to call a method defined in a different assembly (BTW, you can use this overload in the current assembly, just leave the AssemblyName parameter null).

Now, I found that the suggestion above to use typeof(ParentNamespace.ChildNamespace.MyObject).AssemblyQualifiedName for AssemblyName actually gave me errors, and I could not get that to work. I'd get System.IO.FileLoadException (could not load file or assembly...).

What I did get to work is as follows:

var container = Activator.CreateInstance(@"AssemblyName",@"ParentNamespace.ChildNamespace.MyObject");
MyObject obj = (MyObject)container.Unwrap();
obj.DoStuff();

How do I instantiate a class given its string name?

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