Scanner skipping input for first input on loop

Question

I have a program to write to a text file, just using basic input from the scanner. I have it so it goes through the questions then a yes no to add another input. When the user(or tester being me) inputs y to do it again, it asks the 2 top questions at the same time so it does not get the input for the first question, any reason why this is happening? Here is an example Would you like to create another entry? Y/N y What is the course code for the assignemnt? What is the name of the assignment?

do{
    System.out.println("What is the course code for the assignemnt?")
    course = s.nextLine();
    System.out.println("What is the name of the assignment?");
    gName = s.nextLine();
    System.out.println("What did you get on the assignment?");
    yourGrade = s.nextLine();
    System.out.println("What was the assignment out of?");
    gMax = s.nextLine();
    System.out.println("What was the assignment weighted?");
    gWeight = s.nextLine();

    pw.printf("%s|%s|%s|%s|%s",course, gName, yourGrade, gMax, gWeight);
    pw.println("");
    System.out.println("Would you like to create another entry? Y/N");
    YN = s.next().charAt(0);
}
while(YN == 'Y' || YN == 'y');
    pw.close();
}

I believe it's a duplicate of http://stackoverflow.com/questions/7056749/scanner-issue-when-using-nextline-after-nextxxx http://stackoverflow.com/questions/12867589/nextline-method-in-the-scanner — Sky, Mar 18 '14 at 14:55

score 1 · Accepted Answer · answered Mar 18 '14 at 14:54

1

YN = s.next().charAt(0); won't comsume the end-of-line character which will get consumed by the next nextLine (that is on the next iteration), so you need to to another nextLine after it. Or read a line with nextLine and use charAt(0) on that like this: YN = s.nextLine().charAt(0);

answered Mar 18 '14 at 14:54

jpw

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@Kalkrin Meant nextLine. My bad. Was thinking in another language. – jpw Mar 18 '14 at 14:56

score 1 · Answer 2 · answered Mar 18 '14 at 14:56

1

Use YN = s.nextLine().charAt(0); instead of YN = s.next().charAt(0);

answered Mar 18 '14 at 14:56

anirudh

4,116
2
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score 1 · Answer 3 · answered Mar 18 '14 at 15:06

1

change YN = s.next().charAt(0); to YN = s.nextLine().charAt(0); I changed this here and it worked for me,

answered Mar 18 '14 at 15:06

Nerakai

85
3

Scanner skipping input for first input on loop

3 Answers3