Using $var in $array

Question

I need to use a var in an array:

$var = "abcd";
array( 'Bla: bla', 'Blo: $var', 'Bli: bli');

I'm totally noob at php and google has not answered me...

Thanks,

Variable interpolation only works in double quotes. – mario Mar 18 '14 at 15:05 — mario, Mar 18 '14 at 15:05

muttley91 · Answer 1 · 2014-03-18T15:18:46.240

2

As the others have said, you can use double quotes. Or you can technically use concatenation.

Double Quotes

array( 'Bla: bla', "Blo: $var", 'Bli: bli');

Concatenation

array( 'Bla: bla', 'Blo: ' . $var, 'Bli: bli');

edited Mar 18 '14 at 15:18

answered Mar 18 '14 at 15:08

muttley91

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score 1 · Answer 2 · answered Mar 18 '14 at 15:14

1

As others have mentioned, you can use double quotes or concatenation. You can also use => and leave the variable outside of the quotes. For example:

$var = "blah";

$tester = array("boo"=>$var);

echo $tester["boo"];  // results in blah

answered Mar 18 '14 at 15:14

Matthew Johnson

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score 0 · Answer 3 · answered Mar 18 '14 at 15:06

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Use double quotes ""

array( 'Bla: bla', "Blo: $var", 'Bli: bli');
                   ^         ^

answered Mar 18 '14 at 15:06

Kamehameha

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Using $var in $array

3 Answers3