Converting QBasic CHR$(13)+CHR$(10) to C#

Question

I'm trying to pass a straight ASCII text command through my serial port, something like this:

string cmd = "<ID00><PA>Hello World. ";
template.Serial.WriteLine(cmd);

Serial being a SerialPort property reference. I've also tried 'Write(cmd)' but even though the serial port is open the command never seems to go through. I've found that I'm supposed to add a Carriage return (cr) and a Line Feed (lf) to the end of the message, but I don't know how to do this in C# short of converting everything to bytes but It needs to be passed as ASCII Text from my understanding of the protocol.

I found someone's QBasic source that looks like this:

100 OPEN "COM1:9600,N,8,1,CS,DS,CD" AS 1
200 PRINT #1,"<ID00>";:REM SIGN ADDRESS, 00 FOR ALL
210 PRINT #1,"<PA>";:REM PAGE "A" (MESSAGE NUMBER, A-Z)
220 PRINT #1,"<FQ>";:REM OPTIONAL DISPLAY MODE, (FA-FZ), "APPEAR"
230 PRINT #1,"<CB>";:REM OPTIONAL COLOR CHANGE, (CA-CZ), "RED"
240 PRINT #1,"Hello World";:REM TEXT
250 PRINT #1, CHR$(13)+CHR$(10);:REM MUST END IN CARRIAGE RETURN/LINE FEED

So how would you convert CHR$(13)+CHR$(10) to characters that you append to the end of a string line in c# code to be sent through a serial port?

See http://stackoverflow.com/questions/36976240/c-sharp-char-from-int-used-as-string-the-real-equivalent-of-vb-chr — ib11, Jun 04 '16 at 06:47

score 14 · Accepted Answer · answered Mar 19 '14 at 16:21

14

In literal terms, CHR$(13)+CHR$(10) is ((char)13) + ((char)10), although for legibility, it would be better to use the string "\r\n"

answered Mar 19 '14 at 16:21

l33tmike

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"\r\n" worked like a charm, I've been working on this for almost a week now, thanks for the help... :) – roadmaster Mar 19 '14 at 20:38

Shane Wealti · Answer 2 · 2014-03-19T18:24:20.267

0

Append System.Environment.NewLine to your string. This is the equivalent of "\r\n" on Windows systems (but it will not work on Unix systems).

edited Mar 19 '14 at 18:24

answered Mar 19 '14 at 16:11

Shane Wealti

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Not actually a good idea, he needs \r\n, not the system's default. – Hans Passant Mar 19 '14 at 16:55
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That's true but in most cases this will be equivalent to the old vbCrLf. – Shane Wealti Mar 19 '14 at 18:23

Converting QBasic CHR$(13)+CHR$(10) to C#

2 Answers2