How can I turn an ISO date (20140312120000 or 2014-03-12 12:00:00) into "March 12th, 2014 12:00:00"?.
Thanks.
How can I turn an ISO date (20140312120000 or 2014-03-12 12:00:00) into "March 12th, 2014 12:00:00"?.
Thanks.
You can't parse it with the normal DateTime.Parse method,
DateTime.ParseExact(date, "yyyyMMdd''HHmmss", CultureInfo.InvariantCulture)
DateTime thisDate1 = new DateTime(2014, 3, 12);
Console.WriteLine("Today is " + thisDate1.ToString("MMMM dd, yyyy") + ".");
// The example displays the following output:
// Today is March 12, 2011.
What you want to do is to parse the input string as a DateTime
and then convert it to the form you want. The ParseExact
and ToString
methods will do the job.
public string MyFromat(string s)
{
var inputForms = new string[]
{
"yyyyMMdd''HHmmss",
"yyyy-MM-dd' 'HH':'mm':'ss"
};
var time = DateTime.ParseExact(s, inputForms, , CultureInfo.InvariantCulture);
return time.ToString(""MMMM dd, yyyy HH':'mm':'dd", , CultureInfo.InvariantCulture);
}
Your two example forms are not ISO
. If you want to parse ISO date times, then use DateTimeOffset
for representing the time and use these input forms:
static readonly string[] Iso8061DateTimeForms = new string[]
{
"yyyyMMdd'T'HHmmss",
"yyyyMMdd'T'HHmmss'Z'",
"yyyyMMdd'T'HHmmsszzz",
"yyyyMMdd'T'HHmmss'.'fffffff",
"yyyyMMdd'T'HHmmss'.'fffffff'Z'",
"yyyyMMdd'T'HHmmss'.'fffffffzzz",
"yyyy'-'MM'-'dd'T'HH':'mm':'ss",
"yyyy'-'MM'-'dd'T'HH':'mm':'ss'Z'",
"yyyy'-'MM'-'dd'T'HH':'mm':'sszzz",
"yyyy'-'MM'-'dd'T'HH':'mm':'ss'.'fffffff",
"yyyy'-'MM'-'dd'T'HH':'mm':'ss'.'fffffff'Z'",
"yyyy'-'MM'-'dd'T'HH':'mm':'ss'.'fffffffzzz",
};
The full implementation for parsing an ISO 8061 time is:
public static DateTimeOffset ParseIso8061Time(string s)
{
var styles = DateTimeStyles.AllowWhiteSpaces |
(s.EndsWith("Z")
? DateTimeStyles.AssumeUniversal
: DateTimeStyles.AssumeLocal);
return DateTimeOffset.ParseExact(s, Iso8061DateTimeForms,
CultureInfo.InvariantCulture, styles);
}