Print whole string verbatim in gdb

Question

I'm printing a string(char *) in gdb

(gdb) p l
l=0x9aa1f48 "up2 129104596496602200 19 0 0 3 0 eth1 XX :001CB",'0' <repeats 12 times>, "DC"

Is there a setting to have p print the whole string and not fill inn the "repeats ... ". While at it - also extend the default printable length of a string, p seems to cut off if the string is quite long.

See also http://stackoverflow.com/questions/233328/how-do-i-print-the-full-value-of-a-long-string-in-gdb — John Carter, Feb 28 '10 at 21:14

score 27 · Accepted Answer · answered Feb 12 '10 at 21:50

set print repeats 0

Example:

(gdb) p "aaaaaaaaaaaaaaaaaaaaaaaaaaaaaa"
$6 = 'a' <repeats 30 times>
(gdb) set print repeats 0
(gdb) p "aaaaaaaaaaaaaaaaaaaaaaaaaaaaaa"
$7 = "aaaaaaaaaaaaaaaaaaaaaaaaaaaaaa"
(gdb) set print repeats 10
(gdb) p "aaaaaaaaaaaaaaaaaaaaaaaaaaaaaa"
$8 = 'a' <repeats 30 times>

score 13 · Answer 2 · answered Feb 12 '10 at 21:20

13

Use gdb's printf command like this:

(gdb) printf "%s\n", a
aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa

instead of

(gdb) p a  
$1 = 'a' <repeats 32 times>

answered Feb 12 '10 at 21:20

Todd Hayton

415
1
3
9

score 0 · Answer 3 · answered Feb 12 '10 at 15:14

0

Try:

(gdb) x /s l

answered Feb 12 '10 at 15:14

Paul R

208,748
37
389
560

Still get the "" stuff. – nos Feb 12 '10 at 16:05
That's odd - I get that with `p` but not with `x /s`. – Paul R Feb 12 '10 at 17:07

Print whole string verbatim in gdb

3 Answers3