exec() with timeout argument in php?

Question

I have two exec() function with timeout argument. eg:

<?php
exec("timeout 5 /usr/local/bin/trun 'uptime;ps -elf|grep httpd|wc -l;free -m;mpstat'",$t_uptime);
exec("timeout 5 /usr/local/bin/wrun 'uptime;ps -elf|grep httpd|wc -l;free -m;mpstat'",$t_uptime);
?>

Isn't working. I want exec() stop after 5 sec and next exec() function starts its execution. Please correct this or give some alternative way to stop exec() function

http://stackoverflow.com/questions/9419122/exec-with-timeout — 72DFBF5B A0DF5BE9, Mar 20 '14 at 12:41

score 0 · Answer 1 · answered Mar 20 '14 at 12:42

0

exec — Execute an external program

string exec ( string $command [, array &$output [, int &$return_var ]] )

exec() executes the given command.

answered Mar 20 '14 at 12:42

ankit singh

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score 0 · Answer 2 · answered Mar 20 '14 at 12:43

use this function instead- for more info read http://in2.php.net/function.exec

 function PsExecute($command, $timeout = 5, $sleep = 2) {
        // First, execute the process, get the process ID
        $pid = PsExec($command);

        if( $pid === false )
            return false;

        $cur = 0;
        // Second, loop for $timeout seconds checking if process is running
        while( $cur < $timeout ) {
            sleep($sleep);
            $cur += $sleep;
            // If process is no longer running, return true;
            if( !PsExists($pid) )
                return true; // Process must have exited, success!
        }

        // If process is still running after timeout, kill the process and return false
        PsKill($pid);
        return false;
    }

exec() with timeout argument in php?

2 Answers2