The first parameter of execl is the path of the executable file, my question is that what if there is a space in the path?
My program fails when space exists.
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try: escape it with `"\ "` – Ferenc Deak Mar 23 '14 at 08:24
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2Show your source code. When does your program fail (when it is compiled, or while running)? – Basile Starynkevitch Mar 23 '14 at 08:27
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See [execl(3)](http://man7.org/linux/man-pages/man3/exec.3.html) and [this answer](http://stackoverflow.com/a/12596877/841108). Also, use `perror` (or show `errno`) on failure. – Basile Starynkevitch Mar 23 '14 at 08:58
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possible duplicate of [How to call execl() in C with the proper arguments?](http://stackoverflow.com/questions/12596839/how-to-call-execl-in-c-with-the-proper-arguments) – alk Mar 23 '14 at 16:14
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The system call doesn't parse the strings given to it, i.e., doesn't split at whitespace or anything else. – vonbrand Mar 23 '14 at 17:00
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what if there is a space in the path?
It does not matter, as the exec*() functions do not involve a shell or any kind of command interpreter which might choke on the space, or any other special character.
My program fails when space exists.
Does exec() return? Which value do you find in errno or what does perror() print?
exec(....); /* exec*() function do ot return is successful. */
perror("exec() failed);
alk
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