Get day of the week for last 7 days?

Question

I need the names of the day (Monday, Tuesday, Wednesday, Thuesday, Friday, Saturday, Today).

I know this is a newby question and PHP has a date() function. But I tried and can't figure out how...

Answer 1

Achieving this using the DateTime Class and its format method.

The below code's output changes every day.. Since today is Sunday it starts from Monday , Tuesday... If you run this code on Tuesday , you will be getting output as Thursday , Friday , Saturday .. so on.

<?php

for($i=1;$i<=7;$i++) //<--- Since we know total days in a week is 7.
{
    $date = new DateTime(); //<-- Grabs today's datetime
    $date->add(new DateInterval('P'.$i.'D')); //<--- Passes the current value of $i to add days..
    echo $date->format('l')."<br>";
}

OUTPUT :

Monday
Tuesday
Wednesday
Thursday
Friday
Saturday
Sunday

Working Demo

Answer 2

According to the PHP Manual at http://php.net/manual/en/function.date.php, just use "l" as the format parameter to get the full name of the day.

So 23rd Mar 2014 is a Sunday, as echoed by

<?php
echo date ("l", mktime(0, 0, 0, 3, 23, 2014));
// Echoes Sunday
?>

To get past 7, 6, 5 or 10000 days (or number of days in the future) from the current day, according the information at this page, just use negative or positive integers in a string in the strtotime function:

<?php
$backcount = -4;
echo date ("l", strtotime("$backcount day"));
// Executed on 23 Mar 2014 will give Wednesday
?>

Knowing this, you can apply a for loop to get what you need. And if want "Today" instead of the full name of the current day, just add an if condition to handle the situation where the backcount variable is zero.

Answer 3

you can use jddayofweek to retrieve day of week, it has 3 mode for string containing the day of week, string containing the abbreviated day of week and int represent number of day in week

for($i=0;$i<7;$i++){
    $x=jddayofweek($i,2);
    var_dump($x);
}