How do I define a function signature within a class (without actually defining the function body)

Question

What is the difference between these codes in PHP?

code1:

$func=function($name){
         return "name : ".$name;

};
echo $func('john');// << it is true

code2:

class myclass{
         public $name;
         public $func;

}
$c=new myclass();
$c->func=function($n){
         return "name : ".$n;
};
echo $c->func();// << ?!.. is error

The first code is working properly but the second code gives an error. How can I fix it?
Sidenote: My PHP version is 5.3.4

interesting answers to this in: http://stackoverflow.com/questions/4535330/calling-closure-assigned-to-object-property-directly — Ryan Vincent, Mar 23 '14 at 16:46

score 1 · Answer 1 · answered Mar 23 '14 at 16:43

1

You can fix that using Closures in PHP.

<?php
class A {
    public $name;
    public $func;
}

$cl2 = function($n) {
     return "name : ".$n;
};


$func = Closure::bind($cl2, new A(), 'A');
echo $func('john');

OUTPUT :

name : john

answered Mar 23 '14 at 16:43

Shankar Narayana Damodaran

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My Php does not know this. – jvd Mar 23 '14 at 17:59
What is so active?my php version 5.3.4 – jvd Mar 23 '14 at 18:00
thanks,'Closure' not work for me. but i find from answer 'http://stackoverflow.com/questions/4535330/calling-closure-assigned-to-object-property-directly' – jvd Mar 23 '14 at 18:27

How do I define a function signature within a class (without actually defining the function body)

1 Answers1