Getting Blank instead of a value when using -> in PHP

Question

I am making a web app. In one part of it, I have JS send a JSON string to PHP. The conent of the string is:

{"date":"24-03-2014","Cars":["Cheap","Expensive"]}

I want to convert the string into an object, for which I am doing:

$meta = $_POST["meta"];
$obj = json_decode($meta);
echo $obj->date;

Anyhow, Instead of having 24-03-2014 as the output, I am getting a blank line as the output.

What's wrong? What's the correct way of doing this?

It works well, check if $_POST data is in correct format as u specified. — Abhik Chakraborty, Mar 26 '14 at 15:03
Step one: [Enable error reporting](http://stackoverflow.com/a/6575502/1438393) — Amal Murali, Mar 26 '14 at 15:04
Is error reporting on? What does `$meta` contain? What does `$obj` contain? — steven, Mar 26 '14 at 15:04
It work for me. Are you sure that you have JSON in `meta` parameter? — Gennadiy Litvinyuk, Mar 26 '14 at 15:04

score 0 · Answer 1 · answered Mar 26 '14 at 15:02

Not able to re-produce it:

$jsonStr = '{"date":"24-03-2014","Cars":["Cheap","Expensive"]}';
$jsonObj = json_decode($jsonStr);

var_dump($jsonObj);
var_dump($jsonObj->date);

Outputs:

object(stdClass)[1]
  public 'date' => string '24-03-2014' (length=10)
  public 'Cars' => 
    array (size=2)
      0 => string 'Cheap' (length=5)
      1 => string 'Expensive' (length=9)

string '24-03-2014' (length=10)

Are you sure your $_POST['meta'] is set & has values?

This should really be a (shorter) comment. – superphonic Mar 26 '14 at 15:04 — superphonic, Mar 26 '14 at 15:04

score 0 · Answer 2 · answered Mar 26 '14 at 15:04

0

Below works like a charm. Your $_POST["date"] has not correct value inside. Try var_dump($_POST) to debug it.

<?php
  $input = '{"date":"24-03-2014","Cars":["Cheap","Expensive"]}';
  $meta = $input;
  $obj = json_decode($meta);
  var_dump($obj->date); //Prints string(10) "24-03-2014"
?>

answered Mar 26 '14 at 15:04

makallio85

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Again, should be a comment. – superphonic Mar 26 '14 at 15:05

Getting Blank instead of a value when using -> in PHP

2 Answers2