In Android is it possible for a background service to access the url of the web page a user is currently looking at in their Chrome browser? From what ive read so far this is not possible without root access. Im just asking to see if anyone knows if maybe there is some other standard way of doing it?
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Does this answer your question? [How to get url from browser using accessibility service](https://stackoverflow.com/questions/63880266/how-to-get-url-from-browser-using-accessibility-service) – Jeremy Caney May 17 '22 at 07:12
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yes you can. you can use accessibility service
note: if you're not an accessibility app, Google Play will not allow you on the app store if you use this API. If you're writing a personal app its fine.
example: How to get url from browser using accessibility service
The implementation:
public class UrlInterceptorService extends AccessibilityService {
private HashMap<String, Long> previousUrlDetections = new HashMap<>();
@Override
protected void onServiceConnected() {
AccessibilityServiceInfo info = getServiceInfo();
info.eventTypes = AccessibilityEvent.TYPE_WINDOW_CONTENT_CHANGED;
info.packageNames = packageNames();
info.feedbackType = AccessibilityServiceInfo.FEEDBACK_VISUAL;
//throttling of accessibility event notification
info.notificationTimeout = 300;
//support ids interception
info.flags = AccessibilityServiceInfo.FLAG_REPORT_VIEW_IDS |
AccessibilityServiceInfo.FLAG_RETRIEVE_INTERACTIVE_WINDOWS;
this.setServiceInfo(info);
}
private String captureUrl(AccessibilityNodeInfo info, SupportedBrowserConfig config) {
List<AccessibilityNodeInfo> nodes = info.findAccessibilityNodeInfosByViewId(config.addressBarId);
if (nodes == null || nodes.size() <= 0) {
return null;
}
AccessibilityNodeInfo addressBarNodeInfo = nodes.get(0);
String url = null;
if (addressBarNodeInfo.getText() != null) {
url = addressBarNodeInfo.getText().toString();
}
addressBarNodeInfo.recycle();
return url;
}
@Override
public void onAccessibilityEvent(@NonNull AccessibilityEvent event) {
AccessibilityNodeInfo parentNodeInfo = event.getSource();
if (parentNodeInfo == null) {
return;
}
String packageName = event.getPackageName().toString();
SupportedBrowserConfig browserConfig = null;
for (SupportedBrowserConfig supportedConfig: getSupportedBrowsers()) {
if (supportedConfig.packageName.equals(packageName)) {
browserConfig = supportedConfig;
}
}
//this is not supported browser, so exit
if (browserConfig == null) {
return;
}
String capturedUrl = captureUrl(parentNodeInfo, browserConfig);
parentNodeInfo.recycle();
//we can't find a url. Browser either was updated or opened page without url text field
if (capturedUrl == null) {
return;
}
long eventTime = event.getEventTime();
String detectionId = packageName + ", and url " + capturedUrl;
//noinspection ConstantConditions
long lastRecordedTime = previousUrlDetections.containsKey(detectionId) ? previousUrlDetections.get(detectionId) : 0;
//some kind of redirect throttling
if (eventTime - lastRecordedTime > 2000) {
previousUrlDetections.put(detectionId, eventTime);
analyzeCapturedUrl(capturedUrl, browserConfig.packageName);
}
}
private void analyzeCapturedUrl(@NonNull String capturedUrl, @NonNull String browserPackage) {
String redirectUrl = "your redirect url is here";
if (capturedUrl.contains("facebook.com")) {
performRedirect(redirectUrl, browserPackage);
}
}
/** we just reopen the browser app with our redirect url using service context
* We may use more complicated solution with invisible activity to send a simple intent to open the url */
private void performRedirect(@NonNull String redirectUrl, @NonNull String browserPackage) {
try {
Intent intent = new Intent(Intent.ACTION_VIEW, Uri.parse(redirectUrl));
intent.setPackage(browserPackage);
intent.putExtra(Browser.EXTRA_APPLICATION_ID, browserPackage);
intent.addFlags(Intent.FLAG_ACTIVITY_CLEAR_TOP | Intent.FLAG_ACTIVITY_CLEAR_TASK | Intent.FLAG_ACTIVITY_NEW_TASK | Intent.FLAG_ACTIVITY_SINGLE_TOP);
startActivity(intent);
}
catch(ActivityNotFoundException e) {
// the expected browser is not installed
Intent i = new Intent(Intent.ACTION_VIEW, Uri.parse(redirectUrl));
startActivity(i);
}
}
@Override
public void onInterrupt() { }
@NonNull
private static String[] packageNames() {
List<String> packageNames = new ArrayList<>();
for (SupportedBrowserConfig config: getSupportedBrowsers()) {
packageNames.add(config.packageName);
}
return packageNames.toArray(new String[0]);
}
private static class SupportedBrowserConfig {
public String packageName, addressBarId;
public SupportedBrowserConfig(String packageName, String addressBarId) {
this.packageName = packageName;
this.addressBarId = addressBarId;
}
}
/** @return a list of supported browser configs
* This list could be instead obtained from remote server to support future browser updates without updating an app */
@NonNull
private static List<SupportedBrowserConfig> getSupportedBrowsers() {
List<SupportedBrowserConfig> browsers = new ArrayList<>();
browsers.add( new SupportedBrowserConfig("com.android.chrome", "com.android.chrome:id/url_bar"));
browsers.add( new SupportedBrowserConfig("org.mozilla.firefox", "org.mozilla.firefox:id/url_bar_title"));
return browsers;
}
}
and accessibility service config:
<accessibility-service
xmlns:android="http://schemas.android.com/apk/res/android"
android:description="@string/accessibility_service_description"
android:canRetrieveWindowContent="true"
android:settingsActivity=".ServiceSettingsActivity" />

Majid RigiZadeh
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Please note that if you're not an accessibility app, Google Play will not allow you on the app store if you use this API. If you're writing a personal app its fine. – Gabe Sechan May 17 '22 at 05:18
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Can you [edit] your answer to include more details, instead of relying primarily on the links to demonstrate the solution? Answers should be self-contained. – Jeremy Caney May 17 '22 at 07:11