Access certain location in array of strings

Question

I want to enter in 3 names into the array. Then I want to access the position of the second character in the second name.

First of all I get an out of bounds exception in line 13. Also, the second for loop I know is completely off so excuse that.

Why am I getting the exception and how would I access certain character positions in certain strings?

class Names
{
    public static void main(String[]args)
    {
        int index;
        String names[];
        names = new String [3];

        for(index = 1; index <= names.length; index++)
            {
                System.out.println("Enter name " + index);
                names[index] = EasyIn.getString();
            }
        for(index = 0; index < names.length; index++)
            {
                System.out.println(names[1][2]);
            }
    }
}

Look at this thread http://stackoverflow.com/questions/11229986/get-string-character-by-index-java — RB-Develop, Apr 01 '14 at 11:29

Petr Mensik · Answer 1 · 2014-04-01T11:36:05.153

You can create static array and than read the value from it

String[] array = {"Peter", "John", "Andre"}; //now you have three items in array
char secondChar = array[1].charAt(1); //first get second element, than get second char from it

So now secondChar is o - also remember that arrays starts from 0 so that's why index 1 means second item in the array - same applies for charAt, String is just basically array of characters.

score 1 · Answer 2 · answered Apr 01 '14 at 11:35

1

Your code should look like this:

        int index;
        String names[];
        names = new String [3];

        for(index = 0; index < names.length; index++)
        {
            System.out.println("Enter name " + index);
            names[index] = EasyIn.getString();
        }
        for(index = 0; index < names.length; index++)
        {
            if (names[index] != null && names[index].length() > 2)
                System.out.println(names[index].charAt(2));
        }

answered Apr 01 '14 at 11:35

Andi Krusch

1,383
8
6

OK, just one more thing. This only allows me to enter 2 names. Once I enter 2 names it skips to the second for loop immediately without allowing me to enter the third name. – Pizzaman Apr 01 '14 at 11:43
I don't know what your "EasyIn.getStrig()" function is doing, but it is definitely called three times. You should see the output. – Andi Krusch Apr 01 '14 at 11:46

score 1 · Accepted Answer · answered Apr 01 '14 at 11:36

A couple of things.

You can make the array of String objects in one go like String[] names = new String[3].

In your first loop you start like this:

for(index = 1; index <= names.length; index++)

That is wrong, you start with your index at 0 unless you want to skip the first element. Then you define index <= names.length;, which is also wrong. The length returns the actual length, but we now know an array starts at 0. You should define it like this:

for(index = 0; index < names.length; index++)

As others have said before, if you want to get a certain char from the string you use `myString.charAt( )', so in your case you should write something like this:

System.out.println(names[<an index>].charAt(2));

score 1 · Answer 4 · answered Apr 01 '14 at 11:41

try this:

in ur first loop:

for(index = 0; index < names.length; index++)

remove ur second loop as don't wana show each element, u can do it directly like this:

System.out.println(names[1].charAt(1));

score 0 · Answer 5 · answered Apr 01 '14 at 11:30

0

If you want to access a certain character in a string, use mystring.charAt(index)

answered Apr 01 '14 at 11:30

INK

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Access certain location in array of strings

5 Answers5