java.lang.ArrayIndexOutOfBoundsException: length=4; index=4 length array

Question

i have this error:

04-02 11:03:57.922: E/AndroidRuntime(18952): FATAL EXCEPTION: main
04-02 11:03:57.922: E/AndroidRuntime(18952): java.lang.ArrayIndexOutOfBoundsException:   length=4; index=4
04-02 11:03:57.922: E/AndroidRuntime(18952):    at it.nad.cartellecliniche.fragment.SegmentoAnterioreFragment.onTaskComplete(SegmentoAnterioreFragment.java:471)
04-02 11:03:57.922: E/AndroidRuntime(18952):    at it.nad.cartellecliniche.asynctask.LookupTask.onPostExecute(LookupTask.java:279)
04-02 11:03:57.922: E/AndroidRuntime(18952):    at it.nad.cartellecliniche.asynctask.LookupTask.onPostExecute(LookupTask.java:1)
04-02 11:03:57.922: E/AndroidRuntime(18952):    at android.os.AsyncTask.finish(AsyncTask.java:631)
04-02 11:03:57.922: E/AndroidRuntime(18952):    at android.os.AsyncTask.access$600(AsyncTask.java:177)
04-02 11:03:57.922: E/AndroidRuntime(18952):    at android.os.AsyncTask$InternalHandler.handleMessage(AsyncTask.java:644)
04-02 11:03:57.922: E/AndroidRuntime(18952):    at android.os.Handler.dispatchMessage(Handler.java:99)
04-02 11:03:57.922: E/AndroidRuntime(18952):    at android.os.Looper.loop(Looper.java:137)
04-02 11:03:57.922: E/AndroidRuntime(18952):    at android.app.ActivityThread.main(ActivityThread.java:5414)
04-02 11:03:57.922: E/AndroidRuntime(18952):    at java.lang.reflect.Method.invokeNative(Native Method)
04-02 11:03:57.922: E/AndroidRuntime(18952):    at java.lang.reflect.Method.invoke(Method.java:525)
04-02 11:03:57.922: E/AndroidRuntime(18952):    at com.android.internal.os.ZygoteInit$MethodAndArgsCaller.run(ZygoteInit.java:1187)
04-02 11:03:57.922: E/AndroidRuntime(18952):    at com.android.internal.os.ZygoteInit.main(ZygoteInit.java:1003)
04-02 11:03:57.922: E/AndroidRuntime(18952):    at dalvik.system.NativeStart.main(Native Method)

this is the code:

else if (typeTask.equals("LookupSegmentoAnteriore")) {

            switch (resultOperation) {
                case 200: {
                    Object[] lista = (Object[]) output[2];

                    listaBulbo = (String[])lista[0];
                    Arrays.sort(listaBulbo);
                    listaApparatoLacrimale = (String[])lista[1];
                    Arrays.sort(listaApparatoLacrimale);
                    listaPalpebre = (String[])lista[2];
                    Arrays.sort(listaPalpebre);
                    listaCongiuntiva = (String[])lista[3];
                    Arrays.sort(listaCongiuntiva);
                    listaCornea = (String[])lista[4];
                    Arrays.sort(listaCornea);
                    listaAngolo = (String[])lista[5];
                    Arrays.sort(listaAngolo);
                    listaCamera_anteriore = (String[])lista[6];
                    Arrays.sort(listaCamera_anteriore);
                    listaIride = (String[])lista[7];
                    Arrays.sort(listaIride);
                    listaPupilla = (String[])lista[8];
                    Arrays.sort(listaPupilla);
                    listaCristallino = (String[])lista[9];
                    Arrays.sort(listaCristallino);
                    break;
                }
            }
        }

i have added new elements to the list starting

from:

listaCornea = (String[])lista[4];
Arrays.sort(listaCornea);

to:

listaCristallino = (String[])lista[9];
Arrays.sort(listaCristallino);

somebody can help me to resolve this problem? i don't know how to manage the array length problem. I just added the new elements to the list, but i don't know if this is the right form to do it. Do i need to resize my array? how i can do that?

thanks a lot

`length=4; index=4 length array` - Array indexes are **0 based**. For an array of **length = 4**, the index range is **0, ..., 3**. An index = 4 is **out of range**. — Phantômaxx, Apr 02 '14 at 09:22
You cannot resize an array, you can use an [ArrayList](http://docs.oracle.com/javase/7/docs/api/java/util/ArrayList.html) instead. — Max Meijer, Apr 02 '14 at 09:24

score 4 · Accepted Answer · answered Apr 02 '14 at 09:40

problem is your array may declared to have only 4 rooms, that means you can access maximum index of 3 but in above code you gonna access 4th index, then it will complain that your index bound in out,your lenth is 4,

you should use ArrayList instead of array,because Array can't be resize after declaration, but you can add any number of objects to arraylist.

ArrayList<Object> lista=new ArrayList<Object>();

score 2 · Answer 2 · edited Sep 23 '16 at 08:41

Array Index out of bound Exception comes when you try to access index which is not available in your Array.

You have specified. Object[] lista = (Object[]) output[2];

That's means you have two element. first is lista[0] and second is lista[1].

Now you tring to access lista[2]. It means you try to access third element which is actually not available in your Objeact[] lista. So It gives Exception at SegmentoAnterioreFragment.onTaskComplete(SegmentoAnterioreFragment.java:471)

Arraylist is dynamic arraylist. you can add and delete element directly. you not need to specify element limit.

you can use this arraylist instead of Object Array

ArrayList<Object> lista=new ArrayList<Object>();

java.lang.ArrayIndexOutOfBoundsException: length=4; index=4 length array

2 Answers2

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