Java: equalsIgnoreCase + message.startswith?

Question

Got a Question:

How can i combine message.equalsIgnoreCase and message.startswith() ?

i.e:

if (message.startsWith("!spoiler")) {
    String name = sender;
    if (!name.equalsIgnoreCase(ownerchannel)){
        try {
            String spoiler = message.split("!spoiler ")[1];
            sendMessage(channel, "/timeout "+name+" 1");
            if(englishmode == true){
                sendMessage(channel, "Spoiler from "+name+" deleted. Click at 'message deleted' above to read it!");
            }else{
                sendMessage(channel, "Spoiler von "+name+" wurde zensiert. Wer diesen lesen möchte klickt einfach oben auf 'message deleted'.");
            }
        } catch (Exception e) {
        }
    }
}

in my code above, !spoiler xyz will trigger it but !Spoiler xyz wont. how can i combine it to ma tch startswith + ignorecase?

Are you trying to do an AND or OR? Do you want to find matches where the name and the message match your criteria or find when either the name or the message matches your criteria? — Dodd10x, Apr 02 '14 at 18:43
i want the code to react to "!spoiler " as ignorecase and hte message itself should remain as it is. :-) — user3220962, Apr 02 '14 at 18:46

Reimeus · Accepted Answer · 2014-04-02T21:02:38.340

5

You could use toLowerCase

if (message.toLowerCase().startsWith("!spoiler")) {

edited Apr 02 '14 at 21:02

answered Apr 02 '14 at 18:42

Reimeus

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And this wouldn't set the whole message to lowercase when i output the "message"-string? – user3220962 Apr 02 '14 at 18:44
you're not changing the message String itself since `toLowerCase` returns a new `String` (Strings are immutable) – Reimeus Apr 02 '14 at 18:45
This answer is wrong. If you look at the implementation of `String.equalsIgnoreCase()` you will discover that you need to compare **both** lowercase and uppercase versions of the Strings before you can conclusively return `false`. See http://stackoverflow.com/a/38947571/14731 for an alternative answer. – Gili Aug 14 '16 at 23:36

score 0 · Answer 2 · answered Apr 02 '14 at 18:42

0

Convert (a copy of) the string to all lower-case, then just use .startsWith() with the lower-case version of what it's checking for.

answered Apr 02 '14 at 18:42

Mar

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score 0 · Answer 3 · answered Apr 02 '14 at 18:42

0

split requires a regular expression. You would have to use the regular expression for the case you don't care about.

message.split("![Ss]poiler");

answered Apr 02 '14 at 18:42

Makoto

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score 0 · Answer 4 · answered Apr 02 '14 at 18:52

Use the following code to combine both:

if (message.startsWith("!spoiler") && !sender.equalsIgnoreCase(ownerchannel)) {
        String name = sender;
            try {
                String spoiler = message.split("!spoiler ")[1];
                sendMessage(channel, "/timeout "+name+" 1");
                if(englishmode == true){
                    sendMessage(channel, "Spoiler from "+name+" deleted. Click at 'message deleted' above to read it!");
                }else{
                    sendMessage(channel, "Spoiler von "+name+" wurde zensiert. Wer diesen lesen möchte klickt einfach oben auf 'message deleted'.");
                }
            } catch (Exception e) {
            }

    }

Java: equalsIgnoreCase + message.startswith?

4 Answers4