No, you're not right at all, unless you want to sort the pointers by address. The actual address rarely has any meaning though, so that's very unlikely.
For detecting duplicate pointers, you should just compare the pointers as such, that's well-defined.
I would probably go with a solution using uintptr_t
:
static int order_pointers(const void *pa, const void *pb)
{
const uintptr_t a = *(void **) pa, b = *(void **) pb;
return a < b ? -1 : a > b;
}
Haven't tested this, but something like that should work.
The conversion to uintptr_t
is necessary since you cannot validly compare random pointers. I quoth the C99 draft standard, §6.5.8.5:
When two pointers are compared, the result depends on the relative locations in the
address space of the objects pointed to. If two pointers to object or incomplete types both
point to the same object, or both point one past the last element of the same array object,
they compare equal. If the objects pointed to are members of the same aggregate object,
pointers to structure members declared later compare greater than pointers to members
declared earlier in the structure, and pointers to array elements with larger subscript
values compare greater than pointers to elements of the same array with lower subscript
values. All pointers to members of the same union object compare equal. If the
expression P points to an element of an array object and the expression Q points to the
last element of the same array object, the pointer expression Q+1 compares greater than
P. In all other cases, the behavior is undefined.
I bolded the final sentence since that's what applies here.