Buffer to Image with PIL

Question

I'm receiving a buffer from somewhere that contains an image (image_data below), and I'd like to generate a thumbnail from that buffer.

I was thinking to use PIL (well, Pillow), but no success. Here's what I've tried:

>>> image_data
<read-only buffer for 0x03771070, size 3849, offset 0 at 0x0376A900>
>>> im = Image.open(image_data)
Traceback (most recent call last):
  File "<console>", line 1, in <module>
  File "<path>\PIL\Image.py", line 2097, in open
    prefix = fp.read(16)
AttributeError: 'buffer' object has no attribute 'read'
>>> image_data.thumbnail(50, 50)
Traceback (most recent call last):
  File "<console>", line 1, in <module>
AttributeError: 'buffer' object has no attribute 'thumbnail'
>>>

I'm sure there is an easy way to fix this, but I'm not sure how.

@M4rtini: I did not, but it appears Image.frombuffer also expects me to specify the width and height of the picture. Not sure whether that's the right approach? — SaeX, Apr 05 '14 at 11:51

sebdelsol · Accepted Answer · 2014-05-31T22:09:33.287

9

Convert your buffer to a StringIO, which has all the file object's methods needed for Image.open(). You may even use cStringIO which is faster:

from PIL import Image
import cStringIO

def ThumbFromBuffer(buf,size):
    im = Image.open(cStringIO.StringIO(buf))
    im.thumbnail(size, Image.ANTIALIAS)
    return im

edited May 31 '14 at 22:09

answered May 31 '14 at 13:54

sebdelsol

1,045
8
15

3

For python3, the StringIO cStringIO modules have been removed. Instead, `from io import StringIO` https://stackoverflow.com/questions/11914472/stringio-in-python3 – Rob Dec 24 '18 at 18:16

score 2 · Answer 2 · answered May 31 '14 at 17:46

For the sake of completeness, here's what my code ended up to be (with the appreciated help).

def picture_small(request, pk):
    try:
        image_data = Person.objects.get(pk=pk).picture
        im = Image.open(cStringIO.StringIO(image_data))
        im.thumbnail((50, 70), Image.ANTIALIAS)
        image_buffer = cStringIO.StringIO()
        im.save(image_buffer, "JPEG")
        response = HttpResponse(image_buffer.getvalue(), content_type="image/jpeg")
        return response
    except Exception, e:
        raise Http404

Using Django 1.6.

Buffer to Image with PIL

2 Answers2