error in URLconf in django - improperly configured

Question

I want to redirect to my app URL from project url for homepage which is r'^$'. I followed this link. but it did not help. This is the urls.py of my project:

urlpatterns = patterns('',
    url(r'^admin/', include(admin.site.urls)),
    url(r'^$', redirect('home')),
    url(r'^link/', include('link_app.urls')),
    )

This is the urls.py of my app link:

urlpatterns=patterns('',
url(r'^$', LinkListView.as_view(), name='home'),
)

so basically I am aiming at http://127.0.0.1:8000/ and http://127.0.0.1:8000/link/ to be processed by the same view.

I get the following error:

ImproperlyConfigured at /
The included urlconf link_project.urls doesn't have any patterns in it
Request Method: GET
Request URL:    http://127.0.0.1:8000/
Django Version: 1.6
Exception Type: ImproperlyConfigured
Exception Value:    
The included urlconf link_project.urls doesn't have any patterns in it

Again with the code highlighting of random words. Please stop that. — Daniel Roseman, Apr 07 '14 at 20:29
What is you directory structure? Your question refers to `link_app` but the traceback says the problem is with `link_project`. — Alasdair, Apr 07 '14 at 20:57

score 1 · Answer 1 · answered Apr 09 '14 at 21:02

Change your projects urls.py file to modify the

from django.core.urlresolvers import reverse_lazy
from django.views.generic import RedirectView
urlpatterns = patterns('',
url(r'^/$',RedirectView.as_view(url=reverse_lazy('home'))),
url(r'^link/$', LinkedListView.as_view(), name='home'),

The solution assumes that your link app has only one url, for multiple urls in your app try adding a name attribute to url(r'^link/$')

score 0 · Answer 2 · answered Apr 07 '14 at 20:11

If the view which you want to process your urls is the one inside link_app, then do the following:

urls.py of your project:

urlpatterns = patterns('',
    url(r'^admin/', include(admin.site.urls)),
    url(r'^', include('link_app.urls')),
    )

urls.py of your link_app:

urlpatterns=patterns('',
url(r'/$', LinkListView.as_view(), name='home'),
url(r'link/$', LinkListView.as_view(), name='home_link'),
)

Let me know if this worked for you

score 0 · Answer 3 · answered Apr 07 '14 at 20:33

0

Just include your link_app.urls immediately after the admin urls with regex r'^'.

Then use the following patterns within link_app.urls to call the same view:

urlpatterns=patterns('',
    url(r'^$', LinkListView.as_view(), name='home'),
    url(r'^link/$', LinkListView.as_view(), name='link'),
)

answered Apr 07 '14 at 20:33

timo.rieber

3,727
3
32
47

having `r'^'` will redirect even /accounts/ or /register/ to `link_app.urls`, which is not correct right? – eagertoLearn Apr 07 '14 at 20:52
Yes, but you ordering matters, so you can first add url patterns for this urls and put `r'^'` to last position. – timo.rieber Apr 08 '14 at 06:07

score 0 · Accepted Answer · edited May 23 '17 at 11:43

0

You've chosen the wrong answer on the page you linked to. You can't use the redirect shortcut in your URL patterns, since it is not a view. Using RedirectView is the correct approach.

edited May 23 '17 at 11:43

Community

1
1

answered Apr 07 '14 at 21:00

Alasdair

298,606
55
578
516

error in URLconf in django - improperly configured

4 Answers4