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As I'm consuming Twitter API, I got several strings (tweets) containing links, that's it substrings beggining with 'http://'.

How can I get rid of such links, that's it, I want to remove the whole word.

Let's say I have:

'Mi grupo favorito de CRIMINALISTICA. Ultima clase de cuatrimestre http://t.co/Ad2oWDNd4u'

And I want to obtain:

'Mi grupo favorito de CRIMINALISTICA. Ultima clase de cuatrimestre'

Such substrings may appear anywhere along the string

diegoaguilar
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2 Answers2

4

You can use re.sub() to replace all links with an empty string:

>>> import re
>>> pattern = re.compile('http[s]?://(?:[a-zA-Z]|[0-9]|[$-_@.&+]|[!*\(\),]|(?:%[0-9a-fA-F][0-9a-fA-F]))+')
>>> s = 'Mi grupo favorito de CRIMINALISTICA. Ultima clase de cuatrimestre http://t.co/Ad2oWDNd4u'
>>> pattern.sub('', s)
'Mi grupo favorito de CRIMINALISTICA. Ultima clase de cuatrimestre '

It replaces all the links in the string anywhere inside it:

>>> s = "I've used google https://google.com and found a regular expression pattern to find links here https://stackoverflow.com/questions/6883049/regex-to-find-urls-in-string-in-python"
>>> pattern.sub('', s)
"I've used google  and found a regular expression pattern to find links here "

Regular expression was taken from this thread:

Community
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alecxe
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0

You can just do it as:

s[:s.index('http://')-1]

If it doesn't always appear at the end, you can do:

your_list = s.split()
i = 0
while i < len(your_list):
    if your_list[i].startswith('http://'):
        del your_list[i]
    else:
        i+=1
s = ' '.join(your_list)
sshashank124
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