Escape Spaces in this script?

Question

I'm using PHP to create this config file to make an executable and it works fine when the file name doesn't have any spaces but when a file have spaces it doesn't work.

the file name is inside the $readyFile variable.

What can i do to fix this ?

$content = ";!@Install@!UTF-8!
Title=\"Auto-Extract\"
ExecuteFile=\"Runner.exe\"
ExecuteParameters=\"--exe 2999.exe --file $readyFile\"
;!@InstallEnd@!";
$fp = fopen("config.txt","wb");
fwrite($fp,$content);
fclose($fp);

Thanks

Looks like you need to double-escape a set of quotes around it; `\\\"` — Dave, Apr 08 '14 at 19:05
If you're trying to strip the white space in the `$readyFile` variable, this may help: [To strip whitespaces inside a variable in PHP](http://stackoverflow.com/a/1279798/2774955) — 13ruce1337, Apr 08 '14 at 19:08
@Exoon; yeah, but without the dots (you're using in-string substitution; no need to concat) — Dave, Apr 08 '14 at 19:09
@Dave, Worked a treat. Want to add it as an answers so i can accept it ? — Exoon, Apr 08 '14 at 19:15

score 0 · Answer 1 · answered Apr 08 '14 at 19:46

0

You can strip using this regex.

$content=preg_replace('/\s+/', '', $content);

answered Apr 08 '14 at 19:46

Santosh Achari

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score 0 · Answer 2 · answered Apr 09 '14 at 09:36

You can use double-escaped quotes (\\\"):

$content = ";!@Install@!UTF-8!
Title=\"Auto-Extract\"
ExecuteFile=\"Runner.exe\"
ExecuteParameters=\"--exe 2999.exe --file \\\"$readyFile\\\"\"
;!@InstallEnd@!";

When PHP parses the string, it becomes ="--exe 2999.exe --file \"your file here\"", so your inner quotes are still escaped for the call-within-a-call.

Escape Spaces in this script?

2 Answers2