User Input file directory with spaces?

Question

I have a simple code that asks a user to input a folder for the program to work within.

    char MasterDirectory [50];
cout << "Please enter the directory containing the MP3 files you wish to have organised. " << endl;
cin >> MasterDirectory;

GetFileListing(MasterDirectory, "*.mp3");

However, the program doesn't function correctly if the input directory contains a space. Sorry for the rookie question, but how can I enclose the variable of "MasterDirectory" in quotation marks for GetFileListing?

whith std::string instead of a char array it wourld work (besides allocating only 50 characters is qwuite a "short" path) — okaerin, Apr 10 '14 at 10:36
50 was a throwaway number, something I wrote in haste for a test run. Also, apologies for the duplicate topic; can't believe I missed that. — RWest, Apr 10 '14 at 11:12

score 0 · Answer 1 · answered Apr 10 '14 at 10:33

0

You must use cin.getline(MasterDirectory, 50);

answered Apr 10 '14 at 10:33

Prabhu

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score 0 · Accepted Answer · answered Apr 10 '14 at 10:34

0

Better use

cin.getline(MasterDirectory, sizeof(MasterDirectory));

answered Apr 10 '14 at 10:34

Dr. Debasish Jana

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Excellent! That works like a charm. Is sizeof(MasterDirectory) changing the size of the char to the input? – RWest Apr 10 '14 at 11:13
sizeof in this case computes the size of the buffer as declared – Dr. Debasish Jana Apr 10 '14 at 11:15

score 0 · Answer 3 · answered Apr 10 '14 at 10:38

You have to use std::getline to read full line with whitespaces;

can I enclose the variable of "MasterDirectory" in quotation marks?

Just add them to what you read (I suggest using std::string for flexibility):

std::string fileName;
std::cout << "Please enter the directory containing the 
              MP3 files you wish to have organised. " << endl;
std::getline( std::cin, fileName);
GetFileListing( "\"" + fileName + "\"", "*.mp3");

http://ideone.com/Lmi149

User Input file directory with spaces?

3 Answers3