How do I get the year and month from a datetime.datetime object? Here is the code I have problems with:
w = whois.whois('http://stackoverflow.com')
datatime = w.expiration_date
print datatime
the printed object is:
[datetime.datetime(2015, 12, 26, 0, 0), u'2015-12-26T19:18:07-07:00']
How do I get year, month, and day from the part datetime.datetime(2015, 12, 26, 0, 0). I guess I could use regex, but there must be a better way to do this.
It's a list object with one datetime object in it, plus an ISO 8601 string. Just use attributes on the first object:
datatime[0].year
datatime[0].month
datatime[0].day
Demo:
>>> datatime
[datetime.datetime(2015, 12, 26, 0, 0), u'2015-12-26T19:18:07-07:00']
>>> datatime[0]
datetime.datetime(2015, 12, 26, 0, 0)
>>> datatime[0].year
2015
>>> datatime[0].month
12
>>> datatime[0].day
26
Datetime objects has month, year and day attributes.
now = datetime.datetime.now()
print(now.day)
print(now.month)
print(now.year)
You can use calendar for get the month name:
import calendar
calendar.month_name[datetime.datetime.now().month] # Output "April"
Here is how you can get those fields separately as integers:
>>> import datetime
>>> dt = datetime.datetime(2015, 12, 26, 0, 0)
>>> dt.year
2015
>>> dt.month
12
>>> dt.day
26
Or if you want to format just those fields into a string you can use strftime() for example:
>>> dt.strftime('%Y-%m-%d')
'2015-12-26'
In this case it looks like your datatime object is actually a two element list, with a datetime object as the first element and string as the second element. So to get to the datetime object you would just use datatime[0] in place of the dt in my example code.
For anyone looking for this now, here's an updated answer for Python 3.7.4 with time information:
>>> datatime
datetime.datetime(2020, 2, 2, 11, 59, 59)
>>> print(datatime)
2020-02-02 11:59:59
>>> datatime.year
2020
>>> datatime.month
2
>>> datatime.day
2
>>> datatime.hour
11
>>> datatime.minute
59
>>> datatime.second
59
>>> datatime.microsecond
0
