can anyone help me to get each file size individually from a local directory ?.
$files = scandir('soft');
foreach($files as $file) {
echo $file . "<br />";
}
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3 Answers
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From here
$files = scandir('soft');
foreach($files as $file) {
if (!in_array($file,array(".","..")))
{
echo $file . "<br />";
echo filesize('soft/'.$file) . ' bytes';
}
}
Just need to keep in mind that scandir gets only the filenames in that dir, and not the relative path to it. that's why you need to use 'soft/'.$file and not $file
Paul Bele
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1`$file` -> `echo filesize('soft/'.$file) . ' bytes';` instead of `$filename` -> `echo filesize('soft/'.$filename) . ' bytes';` – Sean Apr 12 '14 at 04:42
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sorry i was in a hurry, you are right, modified. Thanks ! – Paul Bele Apr 12 '14 at 04:42
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thanks, but im having a issue, your code shows me 4096 bytes for every files and echoing two extra sizes which files are not exist. – Sahed Apr 12 '14 at 04:44
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try now, it removes the '.' and '..' from the foreach loop – Paul Bele Apr 12 '14 at 04:47
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@seblaze can u help me to get the file sizes in MB ? – Sahed Apr 12 '14 at 04:52
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sure . The function you need to look is : number_format, based on this: http://stackoverflow.com/questions/5501427/php-filesize-mb-kb-conversion you can modify your code : number_format(filesize('tests/'.$file) / 1048576, 2); – Paul Bele Apr 12 '14 at 04:56
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@seblaze thanks very much. can u help me with one more thing please? i need to see the each file last modified date.. is it possible? – Sahed Apr 12 '14 at 05:45
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Yes it's possible. It's something like : date ("F d Y H:i:s.", filemtime('soft/'.$file)); From here : http://www.php.net/manual/en/function.filemtime.php – Paul Bele Apr 12 '14 at 06:03
1
<?
$files = scandir('.');
foreach($files as $file) {
echo filesize($file) . " bytes<br>";
}
?>
Curtis W
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