How to share a file in Android programmatically

Question

I want to share a file(.pdf,.apk etc) using share Intent, I searched google but I find only the code for sharing Image

Intent sharingIntent = new Intent(Intent.ACTION_SEND);
Uri screenshotUri = Uri.parse(path);
sharingIntent.setType("image/png");
sharingIntent.putExtra(Intent.EXTRA_STREAM, screenshotUri);
startActivity(Intent.createChooser(sharingIntent, "Share image using"));

score 24 · Accepted Answer · answered Apr 12 '14 at 06:11

24

You use the same code, you just change the MIME type for the type of data you wish to share. If you wish to share anything regardless of type, use */*

answered Apr 12 '14 at 06:11

Gabe Sechan

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1

Thanks for the answer, You saved my day. – RushDroid Mar 11 '19 at 12:05
@Gabe Sechan How can i share any kind of file from its http url ?? – KJEjava48 Jan 31 '22 at 13:27

score 10 · Answer 2 · answered Aug 08 '19 at 13:40

10

To keep your code pragmatic, use ShareCompat class:

ShareCompat.IntentBuilder.from(this)
        .setStream(uri)
        .setType(URLConnection.guessContentTypeFromName(file.getName()))
        .startChooser();

answered Aug 08 '19 at 13:40

Chintan Soni

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this work and automatically so everything for us, love kotlin – famfamfam Mar 25 '21 at 09:29
1

ShareCompat.IntentBuilder' is deprecated. Deprecated in Java – Mori Nov 25 '21 at 15:06
1

IntentBuilder.from() is deprecated use IntentBuilder() – yousef Abbdolzadeh Jun 29 '22 at 11:19

score 2 · Answer 3 · answered Jan 10 '20 at 17:21

2

This will help you

Intent sharingIntent = new Intent(Intent.ACTION_SEND);
Uri screenshotUri = Uri.parse(path);
sharingIntent.setType("*/*");
sharingIntent.putExtra(Intent.EXTRA_STREAM, screenshotUri);
startActivity(Intent.createChooser(sharingIntent, "Share using"));

answered Jan 10 '20 at 17:21

Hemant N. Karmur

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By using this as-is, you will get `FileUriExposedException` when targeting SDK 24 >. Instead, you should be using a `FileProvider` instead of passing the `Uri` directly. – HB. Apr 22 '20 at 06:15
for this exception FileUriExposedException add this code in your main activity under onCreate method. StrictMode.VmPolicy.Builder builder = new StrictMode.VmPolicy.Builder(); StrictMode.setVmPolicy(builder.build()); – Raj Bedi Oct 11 '20 at 10:50

score 0 · Answer 4 · answered Oct 16 '19 at 06:53

For sdk 24 and up, if you need to get the Uri of a file outside your app storage you have this error.

android.os.FileUriExposedException: file:///storage/emulated/0/MyApp/Camera_20180105_172234.jpg exposed beyond app through ClipData.Item.getUri()

to fix this : exposed beyond app through ClipData.Item.getUri

score 0 · Answer 5 · answered Aug 11 '21 at 08:39

public void ShareFile(String path)
{
    Intent shareToneIntent=new Intent(Intent.ACTION_SEND);
    shareToneIntent.putExtra(Intent.EXTRA_STREAM, Uri.parse(path));
    shareToneIntent.setType(GetMimeType(Uri.parse(path)));
    requireContext().startActivity(shareToneIntent);
}

public String GetMimeType(Uri uri) {
    String mimeType = null;

    if (ContentResolver.SCHEME_CONTENT.equals(uri.getScheme())) {
        mimeType = requireContext().getContentResolver().getType(uri);
    } else {
        String fileExtension = MimeTypeMap.getFileExtensionFromUrl(uri.toString());
        mimeType = MimeTypeMap.getSingleton().getMimeTypeFromExtension(fileExtension.toLowerCase());
    }
    return mimeType;
}

How to share a file in Android programmatically

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