working with arrays in bash and do stuff

Question

I am writing a bash script and need help. This is what I tried:

With the help of @merlin2011

#!/bin/bash

if [ $# -ne 2 ]; then
    echo "Usage: `basename $0` <absolute-path> <number>"
    exit 1
fi

if [ "$(id -u)" != "0" ]; then
    echo "This script must be run as root" 1>&2
    exit 1
fi

#find . -name "$2" -exec mv {} /some/path/here \;
find $1 >> /tmp/test
for line in $(cat `/tmp/test`); do
    echo $line | mv $2 awk -F"/" '{for (i = 1; i < NF; i++) if ($i == "$2") print $(i-1)}'
done

Now I want to check the result of find command from array and then if there were a directory named 2010 then get the absolute path of it. For ecxample:

arr[1]="/path/to/2010/file.db"

Then I want to rename 2010 to parent directory to. My pattern is:

arr[1]="/path/to/2010/file.db"
arr[2]="/path/test/2010/fileee.db"
arr[3]="/path/tt/2010/fileeeee.db"
.
.
.
arr[100]="/path/last/2010/fileeeeeee.db"

Result should be:

mv /path/to/2010/ to
mv /path/test/2010 test
mv /path/tt/2010/ tt
.
.
.
mv /path/last/2010 last

UPDATE:

Totally I want to know how to get a variable inversely in awk...

/path/to/dir1/2010/file.db

I want to search in absolute path then find 2010 and rename it in previous path with / pattern like : awk -F"/" {print [what?]}

tell awk my state is 2010 then print one variable before it by knowing splitter is /

UPDATE

The files dirs and subdirs pattern are:

/path/to/file/efsef/2010/1.db
/path/to/file/hfjh/sdfsf/2010/2.db
/path/to/file/dsf/sdhher/aqwe/sfrt/2010/3.db
.
.
.
/path/to/file/kldf/2010/100.db

I want to rename all 2010 dirs to their parent then tar all .db

This is what exactly I want :)

Answer 1

This answer addresses only the OP's update. My best interpretation is that you are trying to get awk to print the value dir1 inside the string /path/to/dir1/2010/file.db. The following line will achieve it.

awk -F"/" '{for (i = 1; i < NF; i++) if ($i == "2010") print $(i-1)}'

I tested using the following command, which will output dir1.

echo /path/to/dir1/2010/file.db | awk -F"/" '{for (i = 1; i < NF; i++) if ($i == "2010") print $(i-1)}'

Based on your update, you should surround the awk command with the backtic operator.

mv $2 `awk -F"/" '{for (i = 1; i < NF; i++) if ($i == "$2") print $(i-1)}'`

Answer 2

        To implement, we have to do the recursive folder search.

        It should be combination of two commands like find and mv




        find . -name "2010" -exec mv {} /some/path/here \;


Other way shared by merlin2011
    mv $2 awk -F"/" `'{for (i = 1; i < NF; i++) if ($i == "$2") print $(i-1)}'`

Answer 3

Here is awk command:

awk -F"/$2/" '{split($1, a, "/"); system("echo mv " $0 " " a[length(a)]);}' <<< "$1"
mv /path/to/dir1/2010/file.db dir1

Once you're satisfied remove echo in system command.