Integer list join using string.format

Question

As Joining a list that has Integer values with Python, the integer list can be joined by converting str and then joining them.

BTW, I want to get foo bar 10 0 1 2 3 4 5 6 7 8 9 where several data are first(foo, bar), then the size of list 10 and elements follows.

I used string.format as

x = range(10)
out = '{} {} {} {}'.format('foo', 'bar', len(x), x)

out will be foo bar 10 [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]

To solve problem I can rewrite the code as

out = '{} {} {} '.format('foo', 'bar', len(x)) + ' '.join([str(i) for i in x])

It looks inconsistent (mixed string.format and join). I tried

slot = ' {}' * len(x)
out = ('{} {} {}' + slot).format('foo', 'bar', len(x), *x)

It still unattractive I think. Is there a way to join integer list using string.format only?

@LutzHorn inconsistent and unattractive: I want to solve using **one line** `string.format` only. — emesday, Apr 16 '14 at 07:03
Do you actually want to store that string, or is it for printing purpose only? — Ashwini Chaudhary, Apr 16 '14 at 07:13

score 5 · Answer 1 · answered Apr 16 '14 at 06:57

5

I might be missing the point of your question, but you could simply extend the approach you link to as follows:

>>> x = range(10)
>>> out = " ".join(map(str, ["foo", "bar", len(x)] + x))
>>> out
'foo bar 10 0 1 2 3 4 5 6 7 8 9'

answered Apr 16 '14 at 06:57

NPE

score 5 · Accepted Answer · answered Apr 16 '14 at 07:11

5

Since you favor attractiveness, want to use only one line and with format only, you can do

'{} {} {}{}'.format('foo', 'bar', len(x), ' {}' * len(x)).format(*x)
# foo bar 10 0 1 2 3 4 5 6 7 8 9

answered Apr 16 '14 at 07:11

thefourtheye

1

Thank you! Is there as simple as `out = '{} {} {} {}'.format('foo', 'bar', len(x), x)`? – emesday Apr 16 '14 at 07:15
@mskimm Unfortunately, no :( – thefourtheye Apr 16 '14 at 07:17
1

Fancy, I didn't know you could chain format() calls :) – grasshopper Apr 16 '14 at 07:31

score 3 · Answer 3 · answered Apr 16 '14 at 07:16

3

You can simply use the print function for this:

>>> from __future__ import print_function  #Required for Python 2
>>> print('foo', 'bar', len(x), *x)
foo bar 10 0 1 2 3 4 5 6 7 8 9

answered Apr 16 '14 at 07:16

Ashwini Chaudhary

3 Answers3