PHP sqlsrv query to database

Question

I am migrated from MySQL to MS SQL Server, and trying to fetch all data from the routines table. I am connected but unsure how to fetch data with sqlsrv. This is how far I have came:

$conn_array = array (
    "UID" => "sa",
    "PWD" => "root",
    "Database" => "nih_bw",
);
$conn = sqlsrv_connect('BILAL', $conn_array);
if ($conn){
    echo "connected";
    $result = sqlsrv_query($db->db_conn,"SELECT * FROM routines");
}else{
    die(print_r(sqlsrv_errors(), true));
}
sqlsrv_close($conn);
?>

score 15 · Accepted Answer · edited Mar 16 '16 at 19:54

First if I'm not wrong you are storing sqlsrv_connect result into $conn and this result isn't a class obj its a resource, so remove $db->conn

This example, will connect, then fetch if there are resources returned from sqlsrv_query

$conn_array = array (
    "UID" => "sa",
    "PWD" => "root",
    "Database" => "nih_bw",
);
$conn = sqlsrv_connect('BILAL', $conn_array);
if ($conn){
    echo "connected";
    if(($result = sqlsrv_query($conn,"SELECT * FROM routines")) !== false){
        while( $obj = sqlsrv_fetch_object( $result )) {
              echo $obj->colName.'<br />';
        }
    }
}else{
    die(print_r(sqlsrv_errors(), true));
}

Mureinik · Answer 2 · 2014-04-17T11:21:20.653

2

After you've successfully executed the query with sqlsrv_query you can fetch the results, e.g., by using sqlsrv_fetch_array:

$result = sqlsrv_query($db->db_conn, "SELECT * FROM routines");
if($result === false) {
    die( print_r( sqlsrv_errors(), true) );
}

while( $row = sqlsrv_fetch_array($result, SQLSRV_FETCH_ASSOC) ) {
    echo $row['column1'].", ".$row['column2']."<br />";
}

edited Apr 17 '14 at 11:21

answered Apr 17 '14 at 11:13

Mureinik

297,002
52
306
350

I get this error: https://www.dropbox.com/s/lod1s8olf1iwog3/errors.png, its in the $result line it errors. – user3185936 Apr 17 '14 at 11:19
@user3185936 Why are you using `$db->db_conn`? You set connection to `$conn` with `sqlsrv_connect()` so use it: `$result = sqlsrv_query($conn, "SELECT * FROM routines");` – alpakyol Apr 19 '14 at 08:02

score 0 · Answer 3 · answered Apr 17 '14 at 11:14

0

Try this:

while( $row = sqlsrv_fetch_array( $result, SQLSRV_FETCH_ASSOC) ) {
  var_dump($row);
}

sqlsrv_free_stmt($result);

answered Apr 17 '14 at 11:14

Greg Motyl

2,478
17
31

3

When you answer with code, please provide a brief explanation along with the code. – Thom Apr 17 '14 at 11:41

score 0 · Answer 4 · answered Feb 12 '21 at 19:43

$conn_array = array (
    "UID" => "sa",
    "PWD" => "root",
    "Database" => "nih_bw",
);
$conn = sqlsrv_connect('BILAL', $conn_array);
if ($conn){
    echo "connected";
    if(($result = sqlsrv_query($conn,"SELECT * FROM routines")) !== false){
        while( $obj = sqlsrv_fetch_object( $result )) {
              echo $obj->colName.'<br />';
        }
    }
}else{
    die(print_r(sqlsrv_errors(), true));
}

that work great for me, but please any one can help me to display the result on a table ?

I mean this parts :

while( $obj = sqlsrv_fetch_object( $result )) {
              echo $obj->colName.'<br />';
        }

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PHP sqlsrv query to database

4 Answers4

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